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Topic: if a number is even... if it's odd.... (Read 16396 times) previous topic - next topic


Simple question for one of you code gurus out there:

I want an if-then statement that will allow me to test if a given number is even, for example:

Code: [Select]
for (i=0; i<1000; i++)
if (i IS EVEN) { Do something }

Thanks in advance!


Jan 17, 2009, 07:36 pm Last Edit: Jan 17, 2009, 07:37 pm by halley Reason: 1
A number is "even" when you can divide it by two and have zero remainder.

Code: [Select]
if ( (i % 2) == 0) { do_something(); }

A number is "even" if the least significant bit is zero.

Code: [Select]
if ( (i & 0x01) == 0) { do_something(); }



Jan 19, 2009, 04:36 pm Last Edit: Jan 19, 2009, 04:36 pm by Oracle Reason: 1
Also "0" is false, "anything but 0" is true, so:

Code: [Select]
if (i % 2) { // do something odd }

should also work.

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