If I understand correctly.... I believe, by default, one only has access to the first 64K of RAM. Is that correct? What do I have to do to use the remaining 32K? I don't need any memory management whatsoever - I want to use the additional RAM purely as trace buffers for capturing trace data from mutiple state machines and PIDs, so all I need is a single large block of RAM I can use as I want.
Regards,
Ray L.
No, you can use 96kb by default.
These lines are in the linker script:
rom (rx) : ORIGIN = 0x00080000, LENGTH = 0x00040000 /* Flash, 256K /
sram0 (rwx) : ORIGIN = 0x20000000, LENGTH = 0x00010000 / sram0, 64K /
sram1 (rwx) : ORIGIN = 0x20080000, LENGTH = 0x00008000 / sram1, 32K /
ram (rwx) : ORIGIN = 0x20070000, LENGTH = 0x00018000 / sram, 96K */
Notice that "ram" has a length of 96k. Then, if you look further in the linker script you find that everything uses "ram" and not "sram0" or "sram1".
Technically there is 4k more that exists, I believe for the flash controller. But, it isn't contiguous with the 96k and so not quite as easy to access and largely is ignored.
Great! Thanks!
Regards,
Ray L.