No, V is actually the voltage "drop" across the resistor. Eg, if 1K is tied between 5V and
3.3V, the current I = Vdrop / R = (5V - 3.3V) / 1K = 1.7 mA, and not 5 mA or 3.3 mA.
In your example, you mean a 1K(ohm) resistor, right? (just making sure--I'm really new, if you haven't figured it out yet. )So, in this LED (for example), it says "forward voltage drop" is 1.8V-2.2V (DC). Let's say I have a circuit that has 5V---LED---1K(ohm)---Gnd. I want to find the current. I = Vdrop / R = 2.2V / 1K = 2.2mA.
Right? Or am I still confused...
Yeah, the other guys are correct, and as I said you use "the voltage "drop" across the resistor"
to get the current through it. Ohm's Law is for resistors.