So, everytime I sent a message using vw_send, I have to type it like this : vw_send((uint8_t*)msg, length ) ?
Yes.
So, everytime I sent a message using vw_send, I have to type it like this : vw_send((uint8_t*)msg, length ) ?
Yes.
And I have to define what is msg ?
For example msg = '2' ?
PaulS:
So, everytime I sent a message using vw_send, I have to type it like this : vw_send((uint8_t*)msg, length ) ?
Yes.
Any alternatif ? And why got a * ?
Because you're casting a pointer.
Okay, I think I have to read more about pointer and array. Thanks !
vw_send(message, length)
Transmit a message. "message" is an array of the bytes to send, and "length" is the number of bytes stored in the array. This function returns immediately and the message is sent slowly by an interrupt-based background process.
so the message is refering to ((uint8_t*)msg), where msg is any number of words ? It is not array anymore because we include the uint8_t already ?
Thanks
For example msg = '2' ?
No.
2 != '2' != "2"
It is not array anymore because we include the uint8_t already ?
I don't understand what you're saying, but obviously it still is an array, because if it were not, then we wouldn't need to specify a buffer length to transmit.
I mean I can also write like this vw_send(char msg[8],8) ? Instead of writing it like vw_send((uint8_t*)msg,8), char msg[8] = {'1','2','3','4','5','6','7','8'}
Hahaha.. well, so confuse ><
Yes, you can write it like that, but you need to declare the array before the call.
So the purpose of adding (uint8_t*)msg is just to tell that the message is an array of 8 bits.
Am I correct ?
The function expects to be given an array of type uint8_t.
If you give it an array of that type, you don't need the cast.
Okay. Got it.
Means if I give the function unsigned integer with 8 bits(An array), then I do not need to write the keyword uint8_t ?
Correct ?
Heheh
Means if I give the function unsigned integer with 8 bits(An array), then I do not need to write the keyword uint8_t ?
Correct ?
No. An unsigned integer is not an array and it isn't 8 bits.
So, if I want to send a number 2, then how do I wrote it in array of 8 bits ??? Thanks
So, if I want to send a number 2, then how do I wrote it in array of 8 bits ??? Thanks
uint8_t msg[1] = 2;
vw_send(msg, 1);
So from this can I say uint8_t is like a data type ?
For example int variable, so uint8_t variable ?
Thanks
PaulS:
So, if I want to send a number 2, then how do I wrote it in array of 8 bits ??? Thanks
uint8_t msg[1] = 2;
vw_send(msg, 1);
So how about the receiving part ?
void loop()
{
uint8_t buf[VW_MAX_MESSAGE_LEN];
uint8_t buflen = VW_MAX_MESSAGE_LEN;
[b] if (vw_get_message(buf, &buflen)) // Non-blocking[/b]
{
int i;
digitalWrite(13, true); // Flash a light to show received good message
// Message with a good checksum received, dump it.
Serial.print("Got: ");
for (i = 0; i < buflen; i++)
{
Serial.print((char)buf[i]);
Serial.print(" ");
}
Serial.println("");
digitalWrite(13, false);
}
}
What does it means ?
What does it means ?
As you posted it, it means nothing, which is why you should post your code between code tags
Modified ! Thanks . hope you can help me
What does it means ?
In a nutshell, see if there's any data to read, read it if (vw_get_message(buf, &buflen))
, and then print it
for (i = 0; i < buflen; i++)
{
Serial.print((char)buf[i]);
Serial.print(" ");
}
.
Is this the syntax ? Thanks