If I break up the uint16_t type into two uint8_t types and write them seperately. It will read back in a uint16_t type as it should. So, the problem is in the write function. I've almost got it. I'll test some more and post back.
DJ
If I break up the uint16_t type into two uint8_t types and write them seperately. It will read back in a uint16_t type as it should. So, the problem is in the write function. I've almost got it. I'll test some more and post back.
DJ