a= 01
b= 11
c = (a/2 * b/2)*2 + (a%2 * b%2);
c = (0 * 1)* 2 + (1 * 1) = (0 * 2) + 1 = 1
So either robtillaart is wrong, or I am wrong.
Which also is a binary proposition.
I'll leave you to figure that one.
(1/2 * 3/2)*2 + (1%2 * 3%2) = 2.5
It's a two bit machine - difficult to represent fractions and two bits of significance in two bits.