Im not sure by your picture, but I think you may have the 47 cap on it wrong. I think you want positive lead on the chip, and the negative lead on the ground of of chip, or the ground rail.
by reducing the load, I think what he means is change the resistor that sets the current level for the LEDs. I think its 2k in the demo for 20ma, If you change that to 4k, it I think that will set if for about 10ma.