This is the method I've seen everywhere: pinMode(pin, INPUT); digitalWrite(pin, HIGH); What happens if pin already is under a non-ground voltage? Between the pinMode and the digitalWrite the current can freely flow in and damage the pin, right? Isn't more correct the reverse approach? (putting t…

Right method for activating internal pull-up resistors

nickgammon November 15, 2012, 10:14am 2

How would it damage the pin? An input pin is high impedance.

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