How to read a "button"?

Projects Discussion and Showcase Home Automation
1

I need close the circuit touching two wires, so, I take to print what was read, via Serial.println(), the problem is, it's reading wrong (prints 1 and 0 in different positions), I don't know what do, check the images. After I touch both wires, so it shows only 0. Below there is the code:

int pedal = 6;
int led = 13;
int pedalInput = 0;

void setup() {
  Serial.begin(9600);
  pinMode(pedal, INPUT);
  pinMode(led, OUTPUT);
}

void loop() {  
  
  pedalInput = digitalRead(pedal);

  if(pedalInput == HIGH) {
    Serial.println("1");
    digitalWrite(led, HIGH);
  } else {
    Serial.println("0");
    digitalWrite(led, LOW);
  }
}

What can I do to fix this problem?

Thanks so much!!!

Bug.jpg

Bug_OnTouch.jpg

Bug_Scheme.jpg
Bug_Scheme.jpg596×656 135 KB

2

With the two wires not touching you have a "floating input". The input is very high impedance so will pick up noise. When you touch the wires the input is pulled to ground. Change the line "pinMode(pedal, INPUT); to pinMode(pedal, INPUT_PULLUP);
Now when the wires are not touching the input is held high by the internal pullup resistor and will read 1, Touch the wires for 0.

dig sw.jpg
dig sw.jpg760×510 40.2 KB

3

Know it's saying that 'INPUT_PULLUP' was not declared in this scope

4

What version of the IDE are you using? Go back to pinMode(pedal, INPUT); and add digitalWrite(pedal. HIGH): after. That is how to enable internal pullups for an older version of the IDE.

5

Wow man, it's working, thanks!!! I am using an older version.