transistor switch logic . very hard to solve this scenario.

i dont know if im in the right category to post this one.

line follower with 3v power to its dc motor. line follower controlled by arduino.

i want to modify the smaller 3v dc motor to a bigger 6v dc motor by some kind of a reason., since the robot only produce 3v to power the small dc motor. i want to hook the 6v motor to another 6v power source and by using transistor as the 3v will switch the 6v dc motor.

the problem is. the robot can reverse the dc motor whenever its out of track with the line. reverse the +/- vice versa so that the motor can turn forward and reverse.

how can i apply the transistor switch if that is the case?.

if there is a solution, pls give me the diagram.

Your probably referring to this H bridge diagram, http://s.eeweb.com/members/von_wong/answers/1335122304-h-bridge.gif

Or possibly a simple H bridge chip, http://www.elektroda.pl/rtvforum/files-rtvforum/ckt_mtr_1826.jpg

It sounds as if you already have a solution working with the 3V motor. What circuit are you using to drive that? It may be that the existing circuit is already capable of handling the extra voltage and current.

HazardsMind:
Your probably referring to this H bridge diagram, http://s.eeweb.com/members/von_wong/answers/1335122304-h-bridge.gif

Or possibly a simple H bridge chip, http://www.elektroda.pl/rtvforum/files-rtvforum/ckt_mtr_1826.jpg

wow, you are so amazing, it seems you like helping people here...
what kind of transistor do i need? 3v drives the 6v power?...
i have 4 transistor npn tip 41 in my box... is tip 41 to much?

If your following the first link I gave you then, tip 41, should be fine. But looking at the data sheet, its made for high voltage applications. Kinda overkill for your project. You may just want to get some 2n3904 or 2n3906 NPN transistors from RadioShack, or simply a H-bridge DC Driver IC.

If your motor take less than 1A you can use this http://www.farnell.com/datasheets/39120.pdf. It comes in an SO-8 package, so you will need an SMD adapter board to use it unless you are designing your own PCB.

There are some low-cost H-bridges around based on the L293D and L298N bipolar H-bridge chips, but they have a voltage drop of around 2V. So you would need a power supply providing around 8V for your 6V motor if you use one of those.

Another solution is to use a single mosfet to control the motor on/off and speed, and a DPDT relay to reverse it.

dc42:
If your motor take less than 1A you can use this http://www.farnell.com/datasheets/39120.pdf. It comes in an SO-8 package, so you will need an SMD adapter board to use it unless you are designing your own PCB.

There are some low-cost H-bridges around based on the L293D and L298N bipolar H-bridge chips, but they have a voltage drop of around 2V. So you would need a power supply providing around 8V for your 6V motor if you use one of those.

Another solution is to use a single mosfet to control the motor on/off and speed, and a DPDT relay to reverse it.

sorry, in my home there is no ic h-bridges i think.. even 555 is not available

HazardsMind:
If your following the first link I gave you then, tip 41, should be fine. But looking at the data sheet, its made for high voltage applications. Kinda overkill for your project. You may just want to get some 2n3904 or 2n3906 NPN transistors from RadioShack, or simply a H-bridge DC Driver IC.

yes the 1st link . if i need to have the diode to protect the motor whats the code of the diode to be use in mine?. do i really need that diode or its ok without them?

i will take the information of 2n3904 and 2n3906. i hope this transistor is available to the nearest store located in small city from our home. but if 2n3904 is not common, im sure its not available. take note. can it hande the sla 7v 4 amphere battery?

Or, you could control the speed with a transistor, and handle the reverse with a DPDT relay.

No diode needed, but if you are having problems finding the parts, go with the other given alternative from dc42

HazardsMind:
No diode needed, but if you are having problems finding the parts, go with the other given alternative from dc42

what do you mean by dc42?

I think he means my reply #5 in this thread.

dc42:
I think he means my reply #5 in this thread.

ow sorry. as i sad, im sure its not available. but i will check the availability tomorrow.

If you update your profile with the country you live in, then we might be able to suggest suppliers.

dc42:
If you update your profile with the country you live in, then we might be able to suggest suppliers.

i updated my profile as you say. no suppliers here. its Philippines.

Have you tried http://www.farnell.com/distributors/philippines.htm and http://philippines.rs-online.com/web/?

dc42:
Have you tried http://www.farnell.com/distributors/philippines.htm and http://philippines.rs-online.com/web/?

thanks. i will review that link.

by the way an out of topic question since you look like an intelligence person.

can i charge panasonic sla 6v battery (Panasonic LC-RB064P) by my 7.5v 500mA ac to dc adaptor?
take note that the battery is 4ah and my charger has only 500mA....

HazardsMind:
Your probably referring to this H bridge diagram, http://s.eeweb.com/members/von_wong/answers/1335122304-h-bridge.gif

Or possibly a simple H bridge chip, http://www.elektroda.pl/rtvforum/files-rtvforum/ckt_mtr_1826.jpg

i notice in your first link. does it use npn transistors?

because i think you can only use npn for switching device by putting the load before pin 2(collectors pin) ... can you put it after the emitter pin?.

The schematic in the first link does use NPN transistors. I've used that design for years, and it does work.

jaylisto:
can i charge panasonic sla 6v battery (Panasonic LC-RB064P) by my 7.5v 500mA ac to dc adaptor?
take note that the battery is 4ah and my charger has only 500mA....

4ah is a measure of capacity, not current. If your 7.5v adaptor has a regulated output, then you can charge your 6V SLA battery through a silicon diode (1N4001 or similar) and small series resistor (I suggest 10 ohms 3W if the battery is really flat, or about 2 ohms if it is still reading 6V). The higher the resistor value, the longer it will take to charge. If it has an unregulated output, you can still charge your battery through a 10 ohm 3W resistor, but you should stop charging it when the voltage reaches the value specified in the datasheet (probably about 6.8V).