Waiting on a Switch to Stop Moving

Okay, awesome. Typo corrected and the following code works:

boolean debugger = false;  // Verbose output

const int pinCount = 5;
const int pinList[pinCount] = {15, 16, 17, 18, 19};  // A1-A5 set as digital

void setup() {
    for (int i=0; i<pinCount; i++) {
        //pinMode(pinList[i], INPUT_PULLUP);  // Active low, connect switch common to Ground
        pinMode(pinList[i], INPUT);
        digitalWrite(pinList[i], HIGH);
    }

  Serial.begin(9600);
  delay(500);
  Serial.println();
  Serial.println("Serial Activated");

}

void loop() {
    static int previousPosition = -1;
    static boolean unused = false;
    static unsigned long timer = 0;
    int currentPosition = -1;

    // Scan through the switch pins looking for the current position.
    for (byte i=0; i<pinCount; i++) {
        if (digitalRead(pinList[i]) == LOW)
            currentPosition = i;
    }
    
    // Debugger
    if (debugger == true) {
    Serial.print("Running Position: ");
    Serial.println(currentPosition);
    }
    
    // If the current position is different from the previous position:
    if (currentPosition != previousPosition) {
        timer = millis();  // Start a timer.
        unused = true;  // Set an UNUSED flag.
        previousPosition = currentPosition;
    }

    // If the timer reaches "N" and the UNUSED flag is set:
    if (millis() - timer > 1000  && unused  && currentPosition != -1) { // One second
        // Act on the current position. (Your code goes here)
        Serial.print("Current Position: ");
        Serial.println(currentPosition);
        unused = false; // Clear the UNUSED flag.
    }
}

Now the only thing I need is a way to send a once time signal if the switch is in the off position (currentPosition = -1). Any ideas?

Thanks again for all your help.

EDIT: Changed to CODE instead of QUOTE.