Thanks for your reply!
Well I expected something like that.
But I powered only two of them. The third one isnt connected yet.
Currently I run the drivers/steppers in 1/8 microstepping mode. So 200 -> 1600 steps
per revolution.
- Does that mean that the "stepping mode" (1/1,1/2,1/4,1/8) influences the energy they
draw? How to calculate that? - What do you excatly mean by "wave mode"?
- The steppers are energized one after another in my code so I thought that each coil
is only energized at a time. But yes you are right that would be 990mA for only the
steppers if they are powered the same time. In 1/8 microstepping mode would a power
supply of 1.5A be sufficient? Or do I have to calculate 0.33A x 2 per stepper -> 1.98A? - Does microstepping influence the holding torque?
To get around the power supply issue I would buy a new one:
http://www.reichelt.de/Festspannungsnetzteile/SNT-2250-12V/index.html?;ACTION=3;LA=2;ARTICLE=111184;GROUPID=4946;artnr=SNT+2250+12V;SID=12Tz7cdH8AAAIAADWShdY8f8e702b3031b2344d685edfff25f030
Even if you dont speak german -> Its rated: 2250mA, 12V. Would that be sufficient?
My test code:
int motorDirPin = 9;
int motorXPin = 12;
int motorYPin = 11;
int motorZPin =10;
long u = 0;
int stepTime = 0;
LiquidCrystal lcd(7, 6, 5, 4, 3, 2);
void setup() {
lcd.begin(16, 2);
pinMode(motorDirPin, OUTPUT);
pinMode(motorXPin, OUTPUT);
pinMode(motorYPin, OUTPUT);
pinMode(motorZPin, OUTPUT);
digitalWrite(motorDirPin, LOW);
digitalWrite(motorXPin, LOW);
digitalWrite(motorYPin, LOW);
digitalWrite(motorZPin, LOW);
}
void loop() {
stepTime = millis();
for(int i=0;i<1600;i++){
digitalWrite(motorDirPin, HIGH);
digitalWrite(motorXPin, HIGH);
digitalWrite(motorDirPin, HIGH);
digitalWrite(motorZPin, HIGH);
delayMicroseconds(100);
digitalWrite(motorXPin, LOW);
digitalWrite(motorZPin, LOW);
delayMicroseconds(100);
}
stepTime = millis()-stepTime;
//delay(1);
lcd.setCursor(0, 0);
lcd.print(u);
lcd.setCursor(0, 1);
lcd.print("Turnspeed ");
lcd.print(stepTime);
lcd.print("ms");
u++;
delay(1000);
}