I think there needs to be a call to "sensors.requestTemperatures()" and "sensors.getTemp..." in there. Did you look at the sample code for DallasTemperature?
thanks for your answer
"sensors.requestTemperatures()" ( i forgot to write it on here but is present on sketch )
what and where else exatly ?
char temperature = 0 ;
sensors.requestTemperatures();
Serial.println(temperature,DEC);
char buffer[4];
itoa(temperature,buffer,10);
ht1632_putchar(0 , 0, buffer[0]);
ht1632_putchar(6 , 0, buffer[1]);
ht1632_putchar(12 , 0, buffer[2]);
ht1632_putchar(18 , 0, buffer[3]);
ht1632_puttinychar(26 , 0, 'o');
ht1632_putchar(33 , 0, 'C');
delay(150);
thanks
sorry for multiple post
like this ??
char temperature = 0 ;
sensors.requestTemperatures();
temperature = (sensors.getTempCByIndex(0));
Serial.println(temperature,DEC);
char buffer[4];
itoa(temperature,buffer,10);
ht1632_putchar(0 , 0, buffer[0]);
ht1632_putchar(6 , 0, buffer[1]);
ht1632_putchar(12 , 0, buffer[2]);
ht1632_putchar(18 , 0, buffer[3]);
ht1632_puttinychar(26 , 0, 'o');
ht1632_putchar(33 , 0, 'C');
delay(150);
That does look much closer to being right.
getTempCByIndex() does not return a char though, it returns float.
ahhhh so what i should change ??
float temperature = 0 ??
thanks in advance
Actually no, sorry, you were better off with the char, you just won't be getting fractional degrees.
I don't understand.
I' can't convert ?
What's the problem with decimal ?
ie I can't show on this dispaly 22,5 °C ?
I think at this point you should just try it and see.
float temperature=0 ;
sensors.requestTemperatures();
temperature = (sensors.getTempCByIndex(0));
Serial.println(temperature,DEC);
char buffer[4];
itoa(temperature,buffer,10);
ht1632_putchar(0 , 0, buffer[0]);
ht1632_putchar(6 , 0, buffer[1]);
ht1632_putchar(12 , 0, buffer[2]);
ht1632_putchar(18 , 0, buffer[3]);
ht1632_puttinychar(26 , 0, 'o');
ht1632_putchar(33 , 0, 'C');
delay(150);
do not works... e127 °C show
Which part do you suppose is not working-- the part that reads the temperature from the sensor, or the part that displays the temperature on the LCD screen?
I think that inside buffer there is nothing becouse it write 127. The ds 18b20 works perfectly becouse with lcd skecht show the correct temperature
Some questions :
What do you get on the screen if you just output buffer[0] ?
Does the same problem occur if you output the temperature to somewhere else on the screen ?
What happens if you output the temperature twice ? Output it once then output it again without clearing the screen ?
What does your code do to the screen immediately before showing the temperature ?
What happens if you print some text before the temperature ?
What happens if you put a specific value in the buffer without reading the temperature then output it ?
this is with the code posted
( fot.jpg)
i tryed to give a value and it put on display it and it show the value
( exaple 22.50 )
sensors.requestTemperatures();
float TempC = 22.50 ;//sensors.getTempCByIndex(0);
Serial.println(TempC,DEC);
char buffer[4];
itoa(TempC,buffer,10);
ht1632_putchar(0 , 8, buffer[0]);
ht1632_putchar(6 , 8, buffer[1]);
ht1632_putchar(12 , 8, buffer[2]);
ht1632_putchar(18 , 8, buffer[3]);
ht1632_putchar(24 , 8, buffer[3]);
ht1632_puttinychar(32 , 8, 'o');
ht1632_putchar(39 , 8, 'C');
delay(150);
this is the result ( foto22.jpg )
thanks in advance
if i write float TempC = 2250;
show 22500 °C
in serial monitor
show the temperature in this way : 19.4375000000
I think the problem is the decimal
I must divide 19 from 43 without the dot ( or comma )
put 19 into a buffer and the 43 into another buffer
then show it
Right ???
thanks
danielb:
if i write float TempC = 2250;
show 22500 °Cin serial monitor
show the temperature in this way : 19.4375000000
That's strange, I would expect to see: 2250 , wouldn't you?
I think the problem is the decimal
I must divide 19 from 43 without the dot ( or comma )
put 19 into a buffer and the 43 into another buffer
then show it
Right ???
thanks
Pretty much. You will need to adjust your buffer size to 5 and/or adjust your placement on the screen if you want to be able to show "19.43", since that is five characters and your existing code uses four. Or, you could show it as "19.4" and leave it where it is on the screen.
John
yes of course
but i can resolve 22500 problem display but not my BIG problem
If I write
float TempC = sensors.getTempCByIndex(0);
I should see something !!! not e127 that is the error when someting goes wrong !!
I need help for this
resolve 22550 end not 22 50 will be able to resolve !!
hi guys
don't rell me how but now it WORKS !!!
this is the correct code
sensors.requestTemperatures();
int temp = sensors.getTempCByIndex(0);
Serial.println(temp,DEC);
char buffer[4];
itoa(temp,buffer,10);
ht1632_putchar(6 , 8, buffer[0]);
ht1632_putchar(12 , 8, buffer[1]);
// ht1632_putchar(12 , 8, buffer[2]);
// ht1632_putchar(18 , 8, buffer[3]);
ht1632_puttinychar(19 , 8, 'o');
ht1632_putchar(24 , 8, 'C');
delay(150);
only one question ( easy i think )
now it show the temperature in this format XX °C
and if I would like to show decimal ?
ie XX,X °C ?
how I should change it ?
Many thanks
Daniel
how I should change it ?
Based on snippets? Who knows? Post ALL of your code. Right now, we can only guess what sensors is.
int temp = sensors.getTempCByIndex(0);
Does that method return an int? Or a float?
Pauls Thank you for your answer
the kind of sensor il write on the topic and on the top post... SENSOR IS DALLAS DS18B20
the entire code was just posted so I repost
Thank you so much
Daniele
dallas 18B20.txt (15 KB)
// returns temperature in degrees C
float getTempC(uint8_t*);
// returns temperature in degrees F
float getTempF(uint8_t*);
// Get temperature for device index (slow)
float getTempCByIndex(uint8_t);
// Get temperature for device index (slow)
float getTempFByIndex(uint8_t);
So, yes all the methods to get the temperature return a float, not an int.
Your buffer will need to be larger, and you'll need to use ftoa(), instead of itoa(). After that, you'll need to put more characters to the display.