But the factor of 1023 is wrong. It should be 1024.
1. Assume Vref to the ADC = 5V.2. The Full Scale (FS) of the ADC is 5V.3. FS ia 5V; it menas that the all 10 output bits will assume LH-states when 5V is applied to the input of the ADC.4. The decimal count of 11 1111 1111 = 1024-1 = 1023.5. The correct factor is 1023 and not 1024.
5. The correct factor is 1023 and not 1024.
The correct value to use is the number of steps in the interval, 1024. That is simple mathematics, and has nothing to do with the data sheet. Granted, the difference between 1023 and 1024 is not large. However, if you investigate the two-bit and one-bit ADC examples that we suggested in previous posts, you should then understand the point.
It is hard to understand through cognitive process unless clear (theoretical and practical) examples are demonstrated.
Indeed. You haven't done the thought experiments we suggested.Good luck with your efforts to grapple with these very challenging concepts!
5. The Monitor shows: 1023
...Which is what it would have showed had you connected a 1.2V source.Your experiment proves nothing.Go check the datasheet's ADC section.
Your experiment proves nothing.