I am having trouble making a PING))) ultrasonic sensor display distance readout on an LCD. I need help with the code. Please
Well, let's start off by seeing your current code..
You should be able to combine the two examples, LiquidCrystal and the Ping sensor fairly easily.
What exactly would i have to change? i have been trying and trying to get it to work lol i such with this code so far.
EDIT* the code i have so far
#include <LiquidCrystal.h>
// LiquidCrystal display with:
// rs on pin 12
// rw on pin 11
// enable on pin 10
// d4, d5, d6, d7 on pins 5, 4, 3, 2
LiquidCrystal lcd(12, 11, 10, 5, 4, 3, 2);
const int pingPin = 7;
void setup() {
Serial.begin(9600);
lcd.print("in, ");
}
void loop()
{
long duration, inches, cm;
pinMode(pingPin, OUTPUT);
digitalWrite(pingPin, LOW);
delayMicroseconds(2);
digitalWrite(pingPin, HIGH);
delayMicroseconds(5);
digitalWrite(pingPin, LOW);
pinMode(pingPin, INPUT);
duration = pulseIn(pingPin, HIGH);
inches = microsecondsToInches(duration);
cm = microsecondsToCentimeters(duration);
Serial.print(inches);
Serial.print("in, ");
Serial.print(cm);
Serial.print("cm");
Serial.println();
delay(100);
}
long microsecondsToInches(long microseconds)
{
return microseconds / 74 / 2;
}
long microsecondsToCentimeters(long microseconds)
{
return microseconds / 29 / 2;
}
I thought ping sensors used 1 pin for input and output, I only see input here.
(btw, use the Code key (#) above, when you're posting code, makes it much easier to read:))
The code looks okay for the most part, haven't used the 4bitLCD, usually use liquid crystal, but something I'm curious about
// PRINT USING INCHES
lcd.printIn(itoa(val, buf, 10));
lcd.printIn(" in / ");
// PRINT USING CENTIMETERS
lcd.printIn(itoa(val * 2.54, buf, 10));
lcd.printIn(" cm");
Not sure if the first one is really inches, but if so.. you're saying that a CM is equal to 2.54 times the size of an inch. (Maybe your comments are backwards?:X)
But you never stated WHAT your problems are...
are you receiving some data, but it doesn't make sense?
are you not receiving any data?
which ping sensor is it? Some have 2 pins for the input and output, but others just use one. Both can work with the Arduino, but have to adjust your code.. and the code you're using suggests, uhh.. that your ping sensor is working all the time.
Take a look at the ping example with the IDE. You first need to put the output pin HIGH, then read the input. I'm not seeing where you put the sensor high for the reading. Your code would probably work with some analog sensor, such as an LDR, potentiometer, sharp sensor.. etc.
/* Ping))) Sensor
This sketch reads a PING))) ultrasonic rangefinder and returns the
distance to the closest object in range. To do this, it sends a pulse
to the sensor to initiate a reading, then listens for a pulse
to return. The length of the returning pulse is proportional to
the distance of the object from the sensor.
The circuit:
* +V connection of the PING))) attached to +5V
* GND connection of the PING))) attached to ground
* SIG connection of the PING))) attached to digital pin 7
http://www.arduino.cc/en/Tutorial/Ping
created 3 Nov 2008
by David A. Mellis
modified 30 Jun 2009
by Tom Igoe
*/
// this constant won't change. It's the pin number
// of the sensor's output:
const int pingPin = 7;
void setup() {
// initialize serial communication:
Serial.begin(9600);
}
void loop()
{
// establish variables for duration of the ping,
// and the distance result in inches and centimeters:
long duration, inches, cm;
// The PING))) is triggered by a HIGH pulse of 2 or more microseconds.
// Give a short LOW pulse beforehand to ensure a clean HIGH pulse:
pinMode(pingPin, OUTPUT);
digitalWrite(pingPin, LOW);
delayMicroseconds(2);
digitalWrite(pingPin, HIGH);
delayMicroseconds(5);
digitalWrite(pingPin, LOW);
// The same pin is used to read the signal from the PING))): a HIGH
// pulse whose duration is the time (in microseconds) from the sending
// of the ping to the reception of its echo off of an object.
pinMode(pingPin, INPUT);
duration = pulseIn(pingPin, HIGH);
// convert the time into a distance
inches = microsecondsToInches(duration);
cm = microsecondsToCentimeters(duration);
Serial.print(inches);
Serial.print("in, ");
Serial.print(cm);
Serial.print("cm");
Serial.println();
delay(100);
}
long microsecondsToInches(long microseconds)
{
// According to Parallax's datasheet for the PING))), there are
// 73.746 microseconds per inch (i.e. sound travels at 1130 feet per
// second). This gives the distance travelled by the ping, outbound
// and return, so we divide by 2 to get the distance of the obstacle.
// See: http://www.parallax.com/dl/docs/prod/acc/28015-PING-v1.3.pdf
return microseconds / 74 / 2;
}
long microsecondsToCentimeters(long microseconds)
{
// The speed of sound is 340 m/s or 29 microseconds per centimeter.
// The ping travels out and back, so to find the distance of the
// object we take half of the distance travelled.
return microseconds / 29 / 2;
}
Notice how the code puts the pin to an OUTPUT first, then pings, then puts it back into an INPUT.
well that code i got off another site... its not for the parallax ping sensor.. this is what i have come up with
#include <LiquidCrystal.h>
// LiquidCrystal display with:
// rs on pin 12
// rw on pin 11
// enable on pin 10
// d4, d5, d6, d7 on pins 5, 4, 3, 2
LiquidCrystal lcd(12, 11, 10, 5, 4, 3, 2);
const int pingPin = 7;
void setup() {
Serial.begin(9600);
lcd.print("in, ");
}
void loop()
{
long duration, inches, cm;
pinMode(pingPin, OUTPUT);
digitalWrite(pingPin, LOW);
delayMicroseconds(2);
digitalWrite(pingPin, HIGH);
delayMicroseconds(5);
digitalWrite(pingPin, LOW);
pinMode(pingPin, INPUT);
duration = pulseIn(pingPin, HIGH);
inches = microsecondsToInches(duration);
cm = microsecondsToCentimeters(duration);
Serial.print(inches);
Serial.print("in, ");
Serial.print(cm);
Serial.print("cm");
Serial.println();
delay(100);
}
long microsecondsToInches(long microseconds)
{
return microseconds / 74 / 2;
}
long microsecondsToCentimeters(long microseconds)
{
return microseconds / 29 / 2;
}
So I'm confused, still.
Are you not sure how to use the LCD? Is the PING sensor working? and is the LCD working?
But the code you posted, is exactly the same as the code I posted, but it takes away the comments.. and adds initializing the LiquidCrystal library.. and it IS for the Parallax Ping))) sensor.
So.. does it work when you use the serial monitor?
The code you have only STARTS the LCD, doesn't actually use any commands to print anything to it.
sorry.. what i need help with is adding the commands to get the code to print the distance to the LCD.. i can get ping working and have the distance on the serial monitor... i just dont know how to add the correct LCD commands to that code to get it to display the distance on the LCD
Just use the same commands you use for writing to the LCD...
lcd.setCursor(0, 0);
lcd.print("inches:")
lcd.print(inches);
lcd.setCursor(0, 1);
lcd.print("centimeters:");
lcd.print(cm);
Keep in mind you need to use setCursor if you want them both to display.. and add ("inches") and such, I suggest you look into the liquid crystal examples..
On the right side.
Okay i have it working thanks for the help!!!!
#include <LiquidCrystal.h>
// LiquidCrystal display with:
// rs on pin 12
// rw on pin 11
// enable on pin 10
// d4, d5, d6, d7 on pins 5, 4, 3, 2
LiquidCrystal lcd(12, 11, 10, 5, 4, 3, 2);
// this constant won't change. It's the pin number
// of the sensor's output:
const int pingPin = 7;
void setup() {
lcd.begin(2, 12); // This sets the lcd to a two line, 12 char display
// initialize serial communication:
Serial.begin(9600);
}
void loop()
{
// establish variables for duration of the ping,
// and the distance result in inches and centimeters:
long duration, inches, cm;
// The PING))) is triggered by a HIGH pulse of 2 or more microseconds.
// Give a short LOW pulse beforehand to ensure a clean HIGH pulse:
pinMode(pingPin, OUTPUT);
digitalWrite(pingPin, LOW);
delayMicroseconds(2);
digitalWrite(pingPin, HIGH);
delayMicroseconds(5);
digitalWrite(pingPin, LOW);
// The same pin is used to read the signal from the PING))): a HIGH
// pulse whose duration is the time (in microseconds) from the sending
// of the ping to the reception of its echo off of an object.
pinMode(pingPin, INPUT);
duration = pulseIn(pingPin, HIGH);
// convert the time into a distance
inches = microsecondsToInches(duration);
cm = microsecondsToCentimeters(duration);
Serial.print(inches);
Serial.print("in, ");
Serial.print(cm);
Serial.print("cm");
Serial.println();
lcd.clear();
lcd.print("Inches ");
lcd.print(inches);
lcd.setCursor(0, 1);
lcd.print("Centmtrs ");
lcd.print(cm);
delay(100);
}
long microsecondsToInches(long microseconds)
{
// According to Parallax's datasheet for the PING))), there are
// 73.746 microseconds per inch (i.e. sound travels at 1130 feet per
// second). This gives the distance travelled by the ping, outbound
// and return, so we divide by 2 to get the distance of the obstacle.
// See: http://www.parallax.com/dl/docs/prod/acc/28015-PING-v1.3.pdf
return microseconds / 74 / 2;
}
long microsecondsToCentimeters(long microseconds)
{
// The speed of sound is 340 m/s or 29 microseconds per centimeter.
// The ping travels out and back, so to find the distance of the
// object we take half of the distance travelled.
return microseconds / 29 / 2;
}
Helloo, I am new on this whole arduino thing. I have just recently bought an arduino duomilanove and trying to do a project which used a ping ))) sensor and displaying it on an LCD screen.
I see that you have finally figure things out with yours. can you give me a little pointer on where and how to start my project running??
I see that you have finally figure things out with yours. can you give me a little pointer on where and how to start my project running??
There's full code there. That's more than a little pointer. What ELSE do you need? Does someone need to come over and upload the code for you?