Ah actually that should give me a nice spiral as well.
I'm going to try this and I hope it gives me a spiral as well just a bit sharper:
void fibi2(int endcount, int wait){
int sequence0[4]= {0, 9, 18, 27};
int sequence1[4]= {8, 17, 26, 4};
int sequence2[4]= {16, 25, 5, 12};
int sequence3[4]= {24, 6, 3, 20};
int sequence4[4]= {7, 14, 21, 28};
int sequence5[4]= {15, 22, 29, 3};
int sequence6[4]= {23, 30, 2, 11};
int sequence7[4]= {3, 1, 10, 19};
for (int howmanytimes = 0; howmanytimes < endcount; howmanytimes++){
Tlc.clear();
for (int k = 0; k < 4; k++){
Tlc.set(blue + sequence0[k], bluepower[0]);
Tlc.set(green + sequence0[k], greenpower[0]);
Tlc.set(red + sequence0[k], redpower[0]);
}
for (int k = 0; k < 4; k++){
Tlc.set(blue + sequence1[k], bluepower[1]);
Tlc.set(green + sequence1[k], greenpower[1]);
Tlc.set(red + sequence1[k], redpower[1]);
}
for (int k = 0; k < 4; k++){
Tlc.set(blue + sequence2[k], bluepower[2]);
Tlc.set(green + sequence2[k], greenpower[2]);
Tlc.set(red + sequence2[k], redpower[2]);
}
for (int k = 0; k < 4; k++){
Tlc.set(blue + sequence3[k], bluepower[3]);
Tlc.set(green + sequence3[k], greenpower[3]);
Tlc.set(red + sequence3[k], redpower[3]);
}
for (int k = 0; k < 4; k++){
Tlc.set(blue + sequence4[k], bluepower[4]);
Tlc.set(green + sequence4[k], greenpower[4]);
Tlc.set(red + sequence4[k], redpower[4]);
}
for (int k = 0; k < 4; k++){
Tlc.set(blue + sequence5[k], bluepower[5]);
Tlc.set(green + sequence5[k], greenpower[5]);
Tlc.set(red + sequence5[k], redpower[5]);
}
for (int k = 0; k < 4; k++){
Tlc.set(blue + sequence6[k], bluepower[6]);
Tlc.set(green + sequence6[k], greenpower[6]);
Tlc.set(red + sequence6[k], redpower[6]);
}
for (int k = 0; k < 4; k++){
Tlc.set(blue + sequence7[k], bluepower[7]);
Tlc.set(green + sequence7[k], greenpower[7]);
Tlc.set(red + sequence7[k], redpower[7]);
}
Tlc.update();
delay(wait);
for ( int j = 0; j < 96; j++){
choice[j] = choice[j] + 3;
if (choice[j] > 95 ){
choice[j] = 0;
}
}
}
}