Does that mean 5V is the minimum acceptable voltage, or is the voltage at which the regulator has already become unstable? I have a couple of these so was hoping to use one up in a project that needs 5V and 3.3V (to run a Nokia 5110 LCD only) so wondering if I need to run VCC into this L78L33 rather than taking the 5V output of the L7805 as the input to this regulator as I would with lower drop-off voltage types where the maths is more obvious.
My understanding is that there will be a minimum gap of the drop-out voltage. So if you put in 5V you get out 3.3V. If you put in 4.9V you get out 3.2V and so on. I'm not sure that it is necessarily unstable at that point.
Figure 10 on page 18 seems to suggest that the drop-out amount varies by the current drawn.
The drop out point is the point where the regulator stops regulating. Yes its exact value depends on the current but it is not guaranteed that the output will reduce in step with the dropping input.
I’ve tried L78L33ACZ (different ICs from one tape,TO-92) with V(in)=5.0V with no success – only 3.0V output (multiple measurements done by oscilloscope and multimeter), with no load at all. With V(in)>5.3V output is stable, V(out)=3.3V. Defective IC?