Well, an inductor has high impedance to high frequencies, but low impedance with low frequencies.
I understand you so far..
So without a resistor... well, never mind the graph. Here's what the circuit would look like though:
I see that it burned up but I don't know why
it burned up.
3. Could the first voltage spike be taken care of with a voltage regulator and the second with a diode, or would both be handled by the regulator?
You mean, reducing the first spike by limiting the current?
No, on the voltage graph I see a large, positive spike in voltage. So just add a 12v regulator right after the inductor to limit it to 12v right?
The other spike is negative voltage. Well, a diode will stop that right?
Also, yeah.. and inductor and cap combo make a good isolator.
the name for what I'm trying to build..
Another option is to feed the low-current section through a series resistor, with its own local supply cap. This will make the battery a lower-resistance (therefore, more attractive) supply in comparison.
I see. So you're making the battery the path of least resistance so that it doesn't suck the current and voltage from the camera. Won't the camera still be deprived of current though? As in, the current would be momentarily diverted to the the high amp load starving the low amp load when the high amp load is switched on?