Does the PIR sensor put out too much power to drop the time?
is that a silly question?

It could be - what does it mean?

FYI

Federal Communications Commission (FCC) regulation 47 CFR Ch.1 (10/01/98
Edition) which states:

“Section 22.925 Prohibition on airborne operation of cellular
telephones installed in or carried aboard airplanes, balloons or any
other type of aircraft must not be operated while such aircraft are
airborne (not touching the ground). When any aircraft leaves the
ground, all cellular telephones on board that aircraft must be turned
off. The following notice must be posted on or near each cellular
telephone installed in any aircraft: The user of cellular telephones
while this aircraft is airborne is prohibited by FCC rules, and the
violation of this rule could result in suspension of service and/or a
fine. The user of cellular telephones while this aircraft is on the
ground is subject to FAA (Federal Aviation Administration)
regulations.”

Code:

if (Serial.available() > 0) {
      
      inByte = Serial.read();
      
      if (inByte == '#') {
      
      while (pointer < 4) {
         buffer[pointer] = Serial.read( );  // add the character to the buffer

Check to see if at least one character is available, then read all five of them.
Not good.
Why not check to see if you've got a character before reading it?

it seems to effect the Arduino. Almost as if it's resetting it?

Yes, it is resetting - that is what it is designed to do.

Serial is set at 9600 baud (could this be causing it?)

Shouldn't be a problem.

How are you powering the servo?

Code:

void loop()
{
  for(pos = 0; pos < 180; pos += 180)  // goes from 0 degrees to 180 degrees
  {                                  // in steps of 180°
    myservo.write(pos);              // tell servo to go to position in variable 'pos'
    delay(28000);                       // waits 28s for the servo to reach the position
  }
  for(pos = 180; pos>=1; pos-=180)     // goes from 180 degrees to 0 degrees
  {                                   // in step on 180°
    myservo.write(pos);              // tell servo to go to position in variable 'pos'
    delay(28000);                       // waits 28s for the servo to reach the position
  }

Well, that's one(long winded) way of doing it.
Simpler might be

Code:

void loop()
{
    myservo.write(0);             
    delay(28000);                       
    myservo.write(180);
    delay(28000);
} 

 

Can the arduino change some of the html so that an image is changed dependent on the state of an input?

Display what on what?

Java - Grrrrr.
Nope, sorry, you're stuck with hex,  octal or decimal, but not, it seems, binary.

EDIT: Here's a cunning plan: define all the constants as octal unsigned long (ALWAYS with a leading zero),  so you can see what it is supposed to look like, but convert to binary on the fly as you transmit!
Neat, huh?

He's right - I assumed when you wrote "at the resistors", you meant across the potential divider.

B00011000  or 0b00011000

I'd leave the 5V as it is (assuming the supply voltage really is 5V) , and check that the values of resistors plugged into the potential divider equation are correct.

That's a rising edge trigger?
Doesn't look like it needs inverting then.
Timing looks about right for 4800 too.

On the other hand, it doesn't really look a lot like you originally described it.
Hmm.

How about 5 then?

But i think i need the right value to replace 3.4?

Whatever value is connected to Vref.

...which is why we ask you to post all your code.

Still better watch out for the Serial.read loop to bite you in the ass.

So why didn't you post it?

int[] charA = {  // character set for the letter 'A'
  00011000,  //

• row one

That may look like binary, but it is actually octal.