Pages: [1]   Go Down
Author Topic: 100mA battery discharging circuit  (Read 933 times)
0 Members and 1 Guest are viewing this topic.
malaysia
Offline Offline
Newbie
*
Karma: 0
Posts: 13
View Profile
 Bigger Bigger  Smaller Smaller  Reset Reset

im want to build a discharging circuit using arduino to discharge a 300mAh 8.4v NiMh cell. been doing some research on the web for weeks now and stumbled upon a constant current sink circuit using tl431. The circuit is on page 8 of the datasheet
http://www.100y.com.tw/pdf_file/38-ON-TL431,NCV431.pdf

before building the circuit i would like to get some suggestion from fellow arduinians. Do i have to use high wattage resistor for Rs? or is there any better or easier way to discharge a battery at 100mA??
Logged

0
Offline Offline
Shannon Member
****
Karma: 161
Posts: 10431
Arduino rocks
View Profile
 Bigger Bigger  Smaller Smaller  Reset Reset

You can calculate the dissipation in the resistor very simply - P = IV, V = IR, therefore P = I^2 R.  Most standard through-hole resistors are rated for 0.25 to 0.6W depending on exact type.  For a 2.5V reference and 0.1A discharge that means a 25ohm resistor which is 0.25W, so should be OK (it will run hot).  You could use 4 100ohm resistors in parallel to get 25 ohms and a lot less heating.

But back to the original issue - this rate of discharge means something has to dissipate 8.4 x 0.1 = 0.84W (in the circuit you give it will be mainly the transistor, necessitating a power transistor with perhaps a small heat sink.

A far simpler solution is an 82 ohm 2 or 3W power resistor (1W would be enough but again would be pretty hot).  Battery voltage is fairly constant (till discharged) and thus a resistor will be a constant current sink in effect.

Be careful not to let the battery over-discharge, this can drastically reduce the life of most rechargable batteries.
Logged

[ I won't respond to messages, use the forum please ]

Pages: [1]   Go Up
Jump to: