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Topic: how to switch a LM317 voltage regulator / LED on and off? (Read 7210 times) previous topic - next topic

davivid

another thing I've noticed with this new circuit is its drawing slightly more current 0.72A as opposed to 0.69A. Do I need to adjust it? or does the new circuit draw more current to operate. This project calls for high reliability, so I really cant strain/damage the LED's (Typ IF=700mA) .

That's the 4% I was talking about and is the expected amount.  You can increase the 1.8 ohm resistor to 2.0 and increase the 1K to 2.7K which will drop current back down to about 693ma, or just reduce the 1K to 270 which should put it right at around 703ma.

Where the 1.8 ohm is RL and the 1K is RAdj the formula becomes:

IOut = (1.25 + (RAdj x IAdj))/RL

IAdj is usually 50 uA

Is 700ma the nominal current or the absolute maximum?
Facts just don't care if you ignore them.

davivid

Oh right sorry, I didn't realise that's what you meant.

The only specs I have for the LED is: Forward Voltage = 3.8 and Typ IF=700mA, which I assume means Typical? What does one do in these situations? run it at 700mA, or be cautious and drop it a bit lower?


You could run it at 700 without worrying.  Do you have a heat sink for it or does it come with a heat sink?  It will need to be kept cool somehow.  LEDs hate to get hot.  They should have a temperature specification too.
Facts just don't care if you ignore them.

davivid

Great. I reduced the 1K to 270, and now it reads 0.7A.

I have mounted the LED on a heat sink, which keeps it really cool. I now just need to upgrade the 1.8 ohm resistor since its only rated for 0.6w.

Good.  Sounds like you've got the hang of this.
Facts just don't care if you ignore them.

davivid


And don't forget the heatsinking for the LM317, it'll draw about 5.5W and the 1.8 ohm resistor will dissipate 0.9W remember.



Does that mean the LM317 heatsink should have a Thermal Resistance of 6.6 °C/W?

Thermal Resistance = (60 - AmbientTemp) / Power
Thermal Resistance = (60 - 20) / 5.5
Thermal Resistance = 6.6

Those things are huge!


#22
Apr 26, 2012, 06:22 pm Last Edit: Apr 28, 2012, 06:25 am by BillO Reason: 1
That's a bit of overkill.

With a supply voltage of 7.5 @ .7 amps, the LM317 will be dissipating:
WD = 0.7 x (7.5 - 3.8 - 1.25), or about 1.7 watts.  Let's call it 2 to be safe

They recommend a maximum TJ of 125°C for an LM317, but let's keep it cool and on the safe side at 85°C to factor in junction to case RT.  And we'll put ambient at 25°C, again to be safe.  Then we have:

RT= (85 - 25) / 2, or about 30°C/W should do nicely.
Facts just don't care if you ignore them.

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