Farad = (Ampere per second) / VoltFarad * Volt = Ampere per secondso 2F * 2.7V = 5.4 Ampere per second5.4 Ampere per second = 0.0015 ampere per hour //dividing it by 36000.0015Ah = 1.5mAh
the capacitor voltage is going to go down linearly towards 0V,
Yes, MarkT, you are right. Grumpy Mike already pointed that out.*I was just told that 4 of the capacitors I described at start (so 2.7V & 2F) In parallel would be equal to 75mAh. This information comes from the manufacturer. Does anyone have any idea how they arrive at that conclusion?
Voltage will go down exponentially under constant resistance load, linearly under constant current load.
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