Been looking around the forum a lot to find out the answer to my question. Still not done yet actually. But might as well ask this is the mean time:I have a driver that can only put out 1Amp at 1.5V (called L293D dual H-Bridge). I have a motor that needs 2Amps at 2.8 volts. what happens when I put them together?A motor driver that can only supply 1.5v output, that doesn't sound correct. The problem is of course the current rating well below what the motor can require depending on drive voltage and load on the motor. Some motor drivers have over-current detection and cut-off protection, some I suppose don't and you can risk damage if overdriven. Will the driver chip burn out? How about this combo: driver gives 1 Amp and 4.5V to 36V (called SN754410 quadruple Half H Driver) used with same motor.Still not rated for enough current to support the motor under all conditions. Recall that a driver doesn't 'force' a specific amount of current to it's load, rather the motor tries to draw a specific amount of current given it's resistance, counter EMF, and mechanical load.I understand that voltage stats are not really important as motors are often run at voltages about thier rated. But rather the current is more important. That's what worries me here. I think know a motor that takes more current than a drive can give will burn out the driver chip.That is correct, unless the driver has build-in overcurrent protection circuit.BTW thanks for all previous help. I just kinda left my previous thread dead as I found more reading material, and will be back to it eventually to beg more help.
I have a driver that can only put out 1Amp at 1.5V (called L293D dual H-Bridge).
DESIGN 19High Current H-Bridge-2 This circuit will deliver up to 3 amps to a 6v motor. Use TIP100 (NPN) and TIP105 (PNP) for 8 amp H-Bridge.
If both high and low sides of the bridge get turned on simultaneously for any reason, you get smoke.
Design 20 looks more safe on this matter, compare to other options, Two additional low power transistors do great work, to ensure there is no through current. At least at low freq. PWM
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