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Topic: what happens if... (Read 484 times) previous topic - next topic


Sep 17, 2012, 06:44 am Last Edit: Sep 17, 2012, 06:48 am by cjdelphi Reason: 1

if the ldr was connected 5v ~~~~ 1k ~~~~ ldr ~~~ A1  

does the voltage divider  no longer work? A1 should act as gnd no?


A1 is not connected tho.
A0 might act as ground if you used
digitalWrite(D14, LOW);
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Typically, an input pin (analog or digital) will NOT "act as ground"; inputs are almost an open-circuit.


digitalWrite(A1, LOW);  //as suggested should do it though....

Turning the pins to low saves a lot of work using an extra pin :) - ok cool thanks


Also would Guarantee the circuit operation... You would Know what state it was in... just by looking at the sketch.

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