Derbyshire
Offline
Newbie
Karma: 0
Posts: 33
|
 |
« on: October 05, 2012, 02:39:45 pm » |
Hi all, this is a basic programming question. I have a set up where a button changes a button state. (ranging from 0-5) What i want to do is: Make some leds flash a few times when a button state is reached. Then Stop these flashing leds and continue with the rest of the program. I am looking at 'for' statements. for example: if (buttonMode == 3) { for(int i = 0; i<5; i++){ Serial.println(i); digitalWrite(7, LOW); digitalWrite(8, LOW); digitalWrite(9, LOW); delay(400);
digitalWrite(7, HIGH); digitalWrite(8, HIGH); digitalWrite(9, HIGH); delay(400); }}}} I am having trouble stopping the code listed above, and I require to play another bit of code after it have been repeated a few times. I have tried inserting [if button state > 3, 'break:'] etc. Basically I am missing some fundamental programming knowledge! Many thanks,
|
|
|
|
« Last Edit: October 05, 2012, 02:42:27 pm by Wi11turner »
|
Logged
|
|
|
|
|
California
Offline
Edison Member
Karma: 41
Posts: 1869
|
 |
« Reply #1 on: October 05, 2012, 02:53:18 pm » |
Basically I am missing some fundamental programming knowledge!
Actually, you are missing the rest of your code. From what it looks like, you have attempted to implement a state machine, but without seeing all of the code, I can't tell how.
|
|
|
|
|
Logged
|
|
|
|
|
UK, Southwest
Offline
Full Member
Karma: 5
Posts: 138
Arduino rocks
|
 |
« Reply #2 on: October 05, 2012, 02:58:06 pm » |
One way of doing what you want is a state machine
Imagine your states are: Idle Any_button_seen Button1_flashing Button_2_flashing
What would make the transition idle->Any_button_seen? How would you decide to go to the state Button1_flashing? If you were in the state Button1_flashing, what should the Arduino do? How would it decide to finish flashing (hint: look at blinkwithoutdelay example) When finished flashing, what state do you think it should go back to?
Look up state machine. Try drawing out the state machine on a sheet of paper. What might make it move from one state to another?
You will need a variable representing a state, and a switch statement.
|
|
|
|
|
Logged
|
|
|
|
|
Global Moderator
Boston area, metrowest
Online
Brattain Member
Karma: 247
Posts: 16533
Available for Design & Build services
|
 |
« Reply #3 on: October 05, 2012, 03:04:13 pm » |
I'd say you were close: while (buttonMode == 3) { int i = 0; while( i<5){ Serial.println(i); digitalWrite(7, LOW); digitalWrite(8, LOW); digitalWrite(9, LOW); delay(400);
digitalWrite(7, HIGH); digitalWrite(8, HIGH); digitalWrite(9, HIGH); delay(400); i=i+1; } button = 4; }
stay in the inner loop, when done change the outer loop condition so it jumps out
|
|
|
|
|
Logged
|
|
|
|
|
Global Moderator
UK
Offline
Brattain Member
Karma: 138
Posts: 19066
I don't think you connected the grounds, Dave.
|
 |
« Reply #4 on: October 05, 2012, 03:12:12 pm » |
Any reason not to use a for loop there?
|
|
|
|
|
Logged
|
Pete, it's a fool looks for logic in the chambers of the human heart.
|
|
|
|
Global Moderator
Boston area, metrowest
Online
Brattain Member
Karma: 247
Posts: 16533
Available for Design & Build services
|
 |
« Reply #5 on: October 05, 2012, 03:17:32 pm » |
I wasn't sure about where to change button to 4 with a for:next, this way seemed clearer to me.
|
|
|
|
|
Logged
|
|
|
|
|
Global Moderator
UK
Offline
Brattain Member
Karma: 138
Posts: 19066
I don't think you connected the grounds, Dave.
|
 |
« Reply #6 on: October 05, 2012, 03:20:05 pm » |
No, the "while" loop is a classic "for"
|
|
|
|
|
Logged
|
Pete, it's a fool looks for logic in the chambers of the human heart.
|
|
|
|
Global Moderator
Boston area, metrowest
Online
Brattain Member
Karma: 247
Posts: 16533
Available for Design & Build services
|
 |
« Reply #7 on: October 05, 2012, 03:23:16 pm » |
Ok, the long hand way of writing it out still works tho, yes? 4:15 on a Friday, feeling a little frazzled ...
|
|
|
|
|
Logged
|
|
|
|
|
Seattle, WA USA
Offline
Brattain Member
Karma: 313
Posts: 35507
Seattle, WA USA
|
 |
« Reply #8 on: October 05, 2012, 03:36:58 pm » |
while (buttonMode == 3) { // Do some stuff button = 4; } How are you intending to exit this loop? Changing the value of button has no effect on buttonMode.
|
|
|
|
|
Logged
|
|
|
|
|
Offline
Newbie
Karma: 0
Posts: 6
|
 |
« Reply #9 on: October 05, 2012, 04:06:00 pm » |
I am guessing you are learning and just building your own sketches to verify you understand (basically, that is where I am).
the for loop works if you set it up as a function instead of inside the void loop.
so for example void loop () {check for a button press, if received check the state kick out to the function that handles that }
function state1 {do stuff}
function state2 {do different stuff}
Your for loop would be setup in the function state1 or 2. When the if loop is done, it would automatically return to void loop and look for another button press.
you might also want to look at debounce (search debounce arduino) I had the issue of my button press being seen more than once changing my state rapidly. Originally I used a delay, but that basically just paused the program instead of keeping multiple button presses from occurring.
|
|
|
|
|
Logged
|
|
|
|
|
UK
Offline
Tesla Member
Karma: 89
Posts: 6388
-
|
 |
« Reply #10 on: October 05, 2012, 06:30:20 pm » |
the for loop works if you set it up as a function instead of inside the void loop.
When the if loop is done, it would automatically return to void loop and look for another button press.
I can't interpret either of those sentences in any way that makes sense.
|
|
|
|
|
Logged
|
|
|
|
|
Global Moderator
Boston area, metrowest
Online
Brattain Member
Karma: 247
Posts: 16533
Available for Design & Build services
|
 |
« Reply #11 on: October 05, 2012, 09:03:04 pm » |
while (buttonMode == 3) { // Do some stuff buttonMode = 4; <<< yeah, little typo there. }
|
|
|
|
|
Logged
|
|
|
|
|
Offline
Newbie
Karma: 0
Posts: 6
|
 |
« Reply #12 on: October 05, 2012, 11:39:48 pm » |
the for loop works if you set it up as a function instead of inside the void loop.
When the if loop is done, it would automatically return to void loop and look for another button press.
I can't interpret either of those sentences in any way that makes sense. how about the for command works if used in a separate function instead of being inside the void loop(). when the if loop has i in the function reach 5 (no longer less than 5), it will return back to the void loop() and wait for another button press. for example void loop () {// general code to look for button press, current state, etc etc
if (button == 3) buttonstate3; }
int butttonstate3() { {for(int i = 0; i < 5; i++) { Serial.println(i); digitalWrite(7, LOW); digitalWrite(8, LOW); digitalWrite(9, LOW); delay(400);
digitalWrite(7, HIGH); digitalWrite(8, HIGH); digitalWrite(9, HIGH); delay(400); } button = 4; }}
|
|
|
|
|
Logged
|
|
|
|
|
Global Moderator
Melbourne, Australia
Offline
Shannon Member
Karma: 218
Posts: 13897
Lua rocks!
|
 |
« Reply #13 on: October 06, 2012, 01:41:25 am » |
the for command works if used in a separate function instead of being inside the void loop(). No. Don't just make stuff up. if (button == 3) buttonstate3; That does not call the function buttonstate3. This does: if (button == 3) buttonstate3 ();
|
|
|
|
|
Logged
|
|
|
|
|
Global Moderator
Melbourne, Australia
Offline
Shannon Member
Karma: 218
Posts: 13897
Lua rocks!
|
 |
« Reply #14 on: October 06, 2012, 01:43:24 am » |
You would have got better answers if you posted all your code in the first place. Don't just excerpt it.
|
|
|
|
|
Logged
|
|
|
|
|
|