that last circuit I guess would work but wouldn't the vout be 11.3ish? Since the. 7v drop of the transistor? But now alos what would I do drive it low? A pulldown would waste energy and steal from the gate voltage as well
Turning it on idk if it takes 1ms to fully turn on but turning off id like to make as fast as possible
basically it will be receiving the output from a 5v comparator deciding whether it is on or off, id like to drive the mosfet in one step if possible but with the smallest footprint
There's no 0.7V drop because it's all about Vsat
As I stated, at 100mA, that gets up to 0.2V. Drawing less current results even less Vsat
It's a tested circuit!
The PNP opens and closes the path to +V (12V), so its output is +V (less Vsat
) when it's on
or it's "open circuit" when it's off
It's pretty fast. The MOSFET switch time will have more to do with your Gate pull-down (and Gate capacitance).
A high from the Arduino output turns the NPN on, which takes the PNP base low, turning the PNP on, and enabling the final output.
The first circuit is the "easiest". Its only drawback is that it needs a high to the NPN to turn the FET off