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[on:]

I am using VirtualWire library (http://www.open.com.au/mikem/arduino/VirtualWire.pdf) and RF transmitter/reciver to communicate between two arduinos.

There is function in this library to send data:
vw_send((uint8_t *)msg, strlen(msg));

I need to send data like this:

string timestamp;
float voltage;
float current;
float power;

DataToSend = timestamp + "," + voltage + "," + current + "," + power;
for example: "2012.10.13, 4.59, 0.36, 1.65";

Is there any solution for this problem?

[Reply #1 on:]

Is there any solution for this problem?

Of course. The sprintf() function comes to mind.

[Reply #2 on:]

It was said somewher on the forum, that sprintf() does not accept floats.

[Reply #3 on:]

And it says elsewhere on the forum different workarounds.

[Reply #4 on:]

Can you post some links/examples please?

[Reply #5 on:]

Can you post some links/examples please?

The usual methods of printing floats involve either printing the whole number and the fractional portion separately, or using dtostrf() to convert the float to a (unformatted) string.

[Reply #6 on:]

It would be more efficent to send the data in binary form:

Code:

  const char * timestamp = "2012.10.13";
  float voltage = 4.59;
  float current = 0.36;
  float power = 1.65;

  int size_of_float = sizeof(float);
  int size_of_timestamp = strlen(timestamp);

  uint8_t buffer[size_of_timestamp+size_of_float*3];
  void *p = buffer;
  memcpy(p, (void *)timestamp, size_of_timestamp);
  p += size_of_timestamp;
  memcpy(p, (void *)&voltage, size_of_float);
  p += size_of_float;
  memcpy(p, (void *)&current, size_of_float);
  p += size_of_float;
  memcpy(p, (void *)&power, size_of_float);

  vw_send(buffer, sizeof(buffer));

And you could also send the timestamp as a 32bit integer instead of a string.

[Reply #7 on:]

It's worth taking into account that VirtualWire has a send limit of 27 bytes per transmission so it's possible that you will have to split your data.