that makes sense that the pins are ground(sink) , but how does that work? how does it know, when to sink of apply current?or changing the PIN mode output to LOW or High, if they are acting are ground what does this setting change, I see why LOW\HIGH would work when they are supply E\I.
so in my really simple circuit. as above to switch the pin (say 13) output to HIGH and this switch's the LED on but wouldn't that apply another 5V to the diode, as well as the fixed 5v pin connected to the common diode?,
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