Imagine a pipe of water, we can have current/voltage, which is the water flowing, when the water stops flowing, there's no more water/current.
Forget using the terms collector and emitter, these are used specifically for transistors.
In that circuit with the switch open the voltage on pin 1 is Vcc,
with the switch closed the voltage on pin 1 is zero or ground.
Without the resistor the voltage on pin 1 would be nothing with the switch open. Nothing is diffrent from zero. Zero is a voltage level that can cause current to flow. Nothing is just not connected to anything, no current can flow from Vcc to nothing.
If pin 1 is connected to both ground and Vcc, why does the connection to ground "overtake" the connection to Vcc, dropping the voltage to 0?
Is there not still a potential difference (voltage) between Vcc and pin 1
how the resistor impacts the connection to Vcc when pin 1 is connected to both it and ground?
when you say "without the resistor on pin 1", you really mean "without the connection to Vcc (including the resistor) on pin 1", right?
Here's a perfect example of something about this that keeps confusing me.I'm working on the understanding that to have current flow, you need an emitter (-) on one side of a circuit, and a collector (+) on the other.
Please enter a valid email to subscribe
We need to confirm your email address.
To complete the subscription, please click the link in the
email we just sent you.
Thank you for subscribing!
via Egeo 16