Go Down

Topic: 2x2x2 cube qeustion (Read 596 times) previous topic - next topic

Tomtin

Nov 24, 2012, 04:14 pm Last Edit: Nov 24, 2012, 04:50 pm by Tomtin Reason: 1
Hi all,

I am new to arduino and as a first try i made a led ube 2x2x2.
I connected the annodes to I/O 13,12,11,10 and the 2 kathodes to 4 and 5.

If i run a simple program and try to light all the leds only one layer will go on.
Why wont both layers go on?

I used no resistors.

My code below

//2x2x2 LED Cube Sequence 1
//By: TT
//23-11-2012
//all lights on/off
int C1 = 13;
int C2 = 12;
int C3 = 11;
int C4 = 10;

int L1 = 3;
int L2 = 4;


void setup() {
  pinMode(C1, OUTPUT);
  pinMode(C2, OUTPUT);
  pinMode(C3, OUTPUT);
  pinMode(C4, OUTPUT);

  pinMode(L1, OUTPUT);
  pinMode(L2, OUTPUT);

}

void loop() {
  digitalWrite(L1, HIGH); //Layer 1 on
  digitalWrite(L2, HIGH); //Layer 2 on
  digitalWrite(C1, HIGH);
  delay(50);
  digitalWrite(C2, HIGH);
  delay(50);
  digitalWrite(C3, HIGH);
  delay(50);
  digitalWrite(C4, HIGH);
  delay(500);
  digitalWrite(C4, LOW);
  digitalWrite(L1, LOW); //Layer 1 Ends
  digitalWrite(C1, LOW);
  digitalWrite(C2, LOW);
  digitalWrite(C3, LOW);
  digitalWrite(L2, LOW); //Layer 2 Ends
 
}

Nick Gammon

Please edit your post, select the code, and put it between [code] ... [/code] tags.

You can do that by hitting the # button above the posting area.
Please post technical questions on the forum, not by personal message. Thanks!

More info:
http://www.gammon.com.au/electronics

CrossRoads

"I used no resistors."

Because you want to damage all your IO pins right off the bat?

Your ordering is a little off
void loop(){
write Anode(s)  HIGH
write cathode1 LOW, pause, write cathode1 HIGH

write Anode(s) HIGH
write cathode2 LOW, pause, write cathode2 HGH
}
Designing & building electrical circuits for over 25 years.  Screw Shield for Mega/Due/Uno,  Bobuino with ATMega1284P, & other '328P & '1284P creations & offerings at  my website.

Go Up