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[on:]

part of code

void rec_tab(){
  byte i=0,chk=0,j=0;
    while(1){
    if (Serial.available()>0){
      in_buff[j] = Serial.read();
      chk^=in_buff[j]; 
      j++;  
      if (j==in_buff[1]+2) break;

      lcd.setCursor(0,1);
      lcd.print(chk,HEX);
    }
  }
  lcd.setCursor(0,0);
  lcd.print("  after break ");
  lcd.print(chk,HEX);
}

Why break clear chk ??
Before break LCD display 0xA3  after break 0x00 ??

[Reply #1 on:]

Have you tried posting down the street at snippets-r-us.com? Here, we get to see ALL of your code, posted using the code icon (with the #), not the quote icon.

[Reply #2 on:]

break isn't clearing chk, your code is changing it.  break exits the innermost enclosing loop or switch statement with immediate effect.

[Reply #3 on:]

break does not break out of "ifs", only loops. Your break leaves the while loop.