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Topic: make calculation off of data sent by Ping )) sensor (Read 522 times) previous topic - next topic

cashflow

i have a ping )) sensor set up...and i want to simply count the number of times that the reading goes above X inches and Y centimeters...here is the code i'm using now:

const int pingPin = 7;

void setup() {
   // initialize serial communication:
   Serial.begin(9600);
}

void loop()
{
   // establish variables for duration of the ping,
  // and the distance result in inches and centimeters:
   long duration, inches, cm;

  // The PING))) is triggered by a HIGH pulse of 2 or more microseconds.
   // Give a short LOW pulse beforehand to ensure a clean HIGH pulse:
   pinMode(pingPin, OUTPUT);
   digitalWrite(pingPin, LOW);
   delayMicroseconds(2);
   digitalWrite(pingPin, HIGH);
   delayMicroseconds(5);
   digitalWrite(pingPin, LOW);

  // The same pin is used to read the signal from the PING))): a HIGH
   // pulse whose duration is the time (in microseconds) from the sending
   // of the ping to the reception of its echo off of an object.
   pinMode(pingPin, INPUT);
   duration = pulseIn(pingPin, HIGH);

  // convert the time into a distance
   inches = microsecondsToInches(duration);
   cm = microsecondsToCentimeters(duration);
   
  Serial.print(inches);
   Serial.print(".");
   Serial.print(cm);
   Serial.print("");
   Serial.println();
   
  delay(10);
}

long microsecondsToInches(long microseconds)
{
   // According to Parallax's datasheet for the PING))), there are
   // 73.746 microseconds per inch (i.e. sound travels at 1130 feet per
   // second).  This gives the distance travelled by the ping, outbound
   // and return, so we divide by 2 to get the distance of the obstacle.
   // See: http://www.parallax.com/dl/docs/prod/acc/28015-PING-v1.3.pdf
   return microseconds / 74 / 2;
}

long microsecondsToCentimeters(long microseconds)
{
   // The speed of sound is 340 m/s or 29 microseconds per centimeter.
   // The ping travels out and back, so to find the distance of the
   // object we take half of the distance travelled.
   return microseconds / 29 / 2;
}

johnwasser

I see the code that prints out the values but I don't see any attempt to compare those values to anything.  Perhaps that should be your next step.
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robtillaart

Quote
i want to simply count the number of times that the reading goes above X inches and Y centimeters

translates exact to
Code: [Select]
if (inches > X && cm > Y) count++;

but I assume this is not exact what you need ;)
Rob Tillaart

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(Please do not PM for private consultancy)


johnwasser


how this code displays the distance?


Code: [Select]

  duration = pulseIn(pingPin, HIGH);

  // convert the time into a distance
   inches = microsecondsToInches(duration);
   
  Serial.print(inches);
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