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Author Topic: Bit manipulation and addition?  (Read 451 times)
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Hey guys,
I have two 4 bit numbers but I want to "combine" (lack of a better word) these into one 8 bit

For example:
firstnumber = 1010
secondnumber = 1100

I want to put these together literally like:
10101100

How do I do this?

And also, if I and that 8 bit number with 15, will I get the firstnumber? And therefore anding with 240, get the second number?

Cheers, Harris
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Poole, Dorset, UK
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first number*8+second number

Mark
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Actually, it would be firstnumber * 16 + secondnumber.

Although this may be more reliable:

result = (firstnumber & 0x0f) << 4 | (secondnumber & 0x0f)

Therefore:

secondnumber = result & 0x0f

firstnumber = (result & 0xf0) >> 4
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I tried Marks method and was wondering why it didnt seem to work, I then tried your method zeb and it worked great! Thanks a bunch as per guys smiley
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Actually, it would be firstnumber * 16 + secondnumber.

Although this may be more reliable:

result = (firstnumber & 0x0f) << 4 | (secondnumber & 0x0f)

Therefore:

secondnumber = result & 0x0f

firstnumber = (result & 0xf0) >> 4

Now that is a complete answer. C can be so nice and concise if you let it be.

Mark meant well, just having a bad hair day.  smiley-wink

Lefty
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Actually, it would be firstnumber * 16 + secondnumber.

Although this may be more reliable:

result = (firstnumber & 0x0f) << 4 | (secondnumber & 0x0f)

Therefore:

secondnumber = result & 0x0f

firstnumber = (result & 0xf0) >> 4

Now that is a complete answer. C can be so nice and concise if you let it be.

Mark meant well, just having a bad hair day.  smiley-wink

Lefty


No need to worry! I definitely appreciate the help from both smiley
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Glad to have been of assistance.
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Poole, Dorset, UK
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Opps, It was the red wine smiley-red

Mark
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