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### Topic: Very simple resistors question (Read 2296 times)previous topic - next topic

#### M4vrick

##### Mar 04, 2013, 08:16 pm
Hello

I have a simple question about calculating resistor.

I have lots of leds driven by negative, wired with one resistor for each one and 2 leds wired together. I can't modify this as it's enclosed in a box. This is the schematic on the left.
I need to lower the current in the leds, to lower the light amount.

My only option is to add a resistor, like on the right schematic. One resistor for 2 leds+resistors.
How can I calculate the new current flowing through the leds or equivalent resistor? Everything I've found on internet is parallel or serial network, but never parallel + serial.

Thank you

#### fungus

#1
##### Mar 04, 2013, 08:54 pm
You know the voltage drop across the left hand network (5V) and you can measure the current flowing through it. That tells you its resistance (Ohm's law).

Now imagine the whole thing is just a big resistor with that value... the rest is easy.
No, I don't answer questions sent in private messages (but I do accept thank-you notes...)

#### A4kash

#2
##### Mar 04, 2013, 11:43 pmLast Edit: Mar 04, 2013, 11:47 pm by A4kash Reason: 1
http://www.cmiyc.com/tutorials/led-basics/
http://www.kpsec.freeuk.com/components/led.htm
How about looking at this first?

#### cmiyc

#3
##### Mar 05, 2013, 12:10 am
The problem is kind of complicated by the LEDs since they aren't linear like the resistors.

This is a good time to make use of Falsted's simulator...

Capacitor Expert By Day, Enginerd by night.  ||  Personal Blog: www.baldengineer.com  || Electronics Tutorials for Beginners:  www.addohms.com

#### MarkT

#4
##### Mar 05, 2013, 12:12 am
If the LEDs are different colours you are likely to run into problems this way - if the same
colour then it will work better (but current distribution won't be as balanced - this may not matter)

Another approach is to PWM the supply to the existing LEDs - reducing the average brightness
without changing the resistors.
[ I will NOT respond to personal messages, I WILL delete them, use the forum please ]

#### DVDdoug

#5
##### Mar 05, 2013, 12:12 am
Quote
You know the voltage drop across the left hand network (5V) and you can measure the current flowing through it. That tells you its resistance (Ohm's law).
Sort of...   Maybe, "Close enough for government work"

The resistance of an LED is not constant like a resistor...  An LED is a non-linear device.  Ohms Law is always true, but when you change the current through the LED, its effective resistance changes.

The voltage drop across the LED is (approximately) constant under normal operating conditions.  When you increase current, its effective resistance decreases.   If its resistance was constant (like a resistor), the voltage would increase proportionally with the current.

#### fungus

#6
##### Mar 05, 2013, 10:40 am

The voltage drop across the LED is (approximately) constant under normal operating conditions.  When you increase current, its effective resistance decreases.

I know...but I think it's (fairly) safe to assume the LEDs are in the mostly-linear zone, not the exponential zone.

No, I don't answer questions sent in private messages (but I do accept thank-you notes...)

#### M4vrick

#7
##### Mar 05, 2013, 12:59 pm

The leds and resistors are strictly the same. So I guess it's simply a serial network and the calculation is easy now !

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