I bought an 80VA 24 volt transformer and ordered a 24V 50W soldering iron (big mistake). Since i would like to get as much power as possible from the transformer i thought of 'overclocking' the iron a bit. I was thinking of turning the AC output of the transformer into DC with the use of a bridge rectifier, and then set the ripple of the output waveform using capacitors. This way i would increase the voltage going to the iron and therefore its power output ( to lets say 70w). The iron's temperature will be monitored and kept constant.My question is: Would it be a good idea to 'overclock' the iron or will it get burned? Thank you in advance
The iron is the hakko 907 which has an inbuilt temp sensor. The thing will be connected to an atmega which will pulse a mosfet (or triac)in order to keep the temperature of the iron constant under any condition (whether soldering IC pins or large components). A large transformer (80W) is a 'problem' since it takes up more space than a lower power one, which doesn't allow for a more compact unit. But since i got the power i thought why not deliver it to the iron (which would theoretically result in faster heating up times and a more responsive iron). My concern is that the heater of the iron will fail as a result of the extra power.
The circuitry is a K type thermocouple isolated from the 24 volts of the iron. If more power is forced through the iron by increasing the transformer voltage, wouldn't this mean more power dissipated at the iron and therefore a higher temperature rise in a shorter period of time? [t:temp, T:time, m:mass, c:specific heat capacity, E:energy, P:Power] (E = mc?t) => E/T = mc*(?t)/T => P = mc*(?t)/TAccording to the equation above, a higher energy input per second will result in a higher temperature rise for a given time, since the mass of the iron and the specific heat capacity of its material are constants.
The atmega, opamps, display etc would't have any problem since they would be powered by a voltage regulator (probably a switching voltage regulator). My concern as i said before is the reliability of the heater of the iron under such conditions.
My concern is that the heater of the iron will fail as a result of the extra power.
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