The point of my breadboard is to lower that 11.7V to 10V.
You ninja'd me, lefty. I'm going to use it to do the dimming function of 2 different meanwell led drivers, ELN60-48P and ELN60-27P(Making separate circuits for each, so just one driver for this example)Here's a link to my first post, which goes into greater detail about what I'm doing. http://arduino.cc/forum/index.php/topic,155564.0.html#msg1166302 Thanks for taking a look!
Adding a 1k resistor to the output didn't change anything, but thanks for the tip, I'll keep that in mind.
Lefty, I'm probably definitely going overboard, 'cause I don't really know what I'm doing. Now, keeping that in mind, what exactly do you mean by two series diodes? Two diodes in series?Yes, Vin > anode > cathode > anode > cathode > resistor > collector of transistor. What kind of diode? Why are two diodes better than one voltage regulator (if it worked)?Any IN400x type diode would be fine, each diode will have a constant forward voltage drop of around .6vdc so two will give 1.2vdc voltage drop so 11.7 - 1.2 = 10.5vdc, three is series would give you 9.9vdc, your choice.Why are two diodes better than one voltage regulator (if it worked)?Linear voltage regulators are designed to power circuitry not to control the signal level of a PWM control signal, that's like using a sledge hammer to hang a picture hook. It's simply the wrong tool for the job at handLeftyYeah, my sketch actually has analogWrite(9,~255); but for simplicity I left that tid-bit out, and as usual, I had to explain it anyway.. so much for simplicity. I should stop taking shortcuts...Afremont, Hmmm...maybe? I went from Vout to R1k to multimeter to ground.
Afremont, after reading your post at least 5 times, I still mostly don't understand anything, but it sounds scary. Someday I'll understand, thanks for trying to educate me!
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