6 and 7 goes to the input pins 1 and 2 while, 10 and 11 go to the input pins 3 and 4(on the other side of the ic...)
This, to me, sounds like you don't know how to count pins on a DIP IC.
First - locate the dot or notch on the end of the IC. Place the IC on its "legs" with that end facing away from you.
Now - if it is a dot - sometimes it will be close to the left edge of the IC as oriented - that is "pin 1" of the IC.
If it is a notch (or similar), the left-most pin at the end with the notch/dot will be "pin 1" of the IC.
Pin 2 of the IC is the next pin on the left-side.
Continue counting down the left side - when you reach the last pin on the left side, then next pin in the count will be on the right side, at the -bottom- of the IC.
Continue counting up the right side, until you reach the last pin.
Thus - on an 8-pin DIP IC - pin 1 is opposite pin 8, pin 2 is opposite pin 7, etc.
On a 28 pin DIP IC (like the ATMega328) - pin 1 is opposite pin 28, pin 2 is opposite pin 27, etc.
In other words, it's a counter-clockwise pattern.
See this diagram for details: http://en.wikipedia.org/wiki/Dual_in-line_package#Orientation_and_lead_numbering