float Voltage=map(Sample, 0, 1023, 0, 3.9611); float Resistance=24900*((5.0/Voltage)-1); float TempInKelvin=1/(0.00129241+0.0002341077*log(Resistance)+0.00000008775468*(pow(log(Resistance), 3))); float TemperatureInCelsius=TempInKelvin-273.15;
When I saw the complex math on this formula, I didn't even try; but I want to know as it maybe useful in the future.
Your planning for things useful in the future might be better devoted to research for simpler alternatives - like using DS18B20s, which don't need any of that stuff
ST-100 I'm using it is 0.1 Celsius
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