Doesn't look right to me. Where is the AC input? It should go to the junction of the diodes with opposite connections. That is the DC comes from the pair of anodes, and pair of cathodes joined and the AC goes in the other pair where an anode and cathode are joined.Draw us a schematic of what you are trying to make.
ah I think you're right. I am still new to reading schematics, but this seems more correct, maybe?https://www.dropbox.com/s/xbwbhmbz054pzb4/photo2.JPG
Quote from: hilukasz on Dec 08, 2013, 08:40 pmah I think you're right. I am still new to reading schematics, but this seems more correct, maybe?https://www.dropbox.com/s/xbwbhmbz054pzb4/photo2.JPGYes looks a lot better to me as well.Where is the AC coming from?That is a 35V working capacitor so the maximum RMS AC you should be using is 24V.
the input is coming from a 12v 1A 12w ac adaptor
Such a device is almost certainly going to be supplying you with DC, not AC.
Quotethe input is coming from a 12v 1A 12w ac adaptorSuch a device is almost certainly going to be supplying you with DC, not AC.
FYI - you can buy a bridge rectifier that has 4 diodes in one package with 4 terminals. Building one yourself is a good learning experience, but I can't remember the last time I built built one.Also, it's a good idea to "derate" you components. The voltage rating on your 1N4007 is fine, but at 1 Amp, you are pushing it to it's limit. When you first power-on, you will likely get quit a bit more than 1A of "inrush" current as the capacitor charges-up. Your diodes will probably survive, but it's good to have some safety margin. (I haven't checked the specs, but they probably can withstand more current for a short time.)
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