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Topic: Power jack for arduino prototyping (Read 369 times) previous topic - next topic

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I found this tutorial for building your own arduino on a breadboard.

http://arduino.cc/en/Main/Standalone

I'm planning to do that on a PCB and also  power the the processor with 12V DC.
The thing is, where should I connect the power jack ?

I would connect it to either pin 7 or 20 but not sure what the difference is between Vcc and AVcc

And also how can I reach to 5V output ? Is it also introduced through voltage divider on the arduino board ?


larryd

#1
Jul 10, 2014, 12:52 am Last Edit: Jul 10, 2014, 12:55 am by LarryD Reason: 1
Quote
power the the processor with 12V DC.

+12 anode of 1N4007 cathode to 7805 regulator input, 7805 regulator output is +5V.
Of course you will power the 7805 with 12V and feed the o/p of the 7805 to the processor VCC(7) and AVcc(20) .
Aref(21) to 100nf to ground.
VCC(7) to 100nF to ground.
AVcc(20) to 100nF to ground.
No technical PMs.
The last thing you did is where you should start looking.

polymorph

5V and -only- 5V connects to both Vcc and AVcc. Do NOT connect 12V to those pins. It should go to ground and the input of the 7805, seen here:



That page is flawed - there should be several 0.1uF bypass caps across both power rails, one right at AVcc, and on ARef.
Steve Greenfield AE7HD
Drawing Schematics: tinyurl.com/23mo9pf - tinyurl.com/o97ysyx - tinyurl.com/q7uqnvn
Multitasking: forum.arduino.cc/index.php?topic=223286.0
gammon.com.au/blink - gammon.com.au/serial - gammon.com.au/interrupts

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