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Author Topic: Power jack for arduino prototyping  (Read 106 times)
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I found this tutorial for building your own arduino on a breadboard.

I'm planning to do that on a PCB and also  power the the processor with 12V DC.
The thing is, where should I connect the power jack ?

I would connect it to either pin 7 or 20 but not sure what the difference is between Vcc and AVcc

And also how can I reach to 5V output ? Is it also introduced through voltage divider on the arduino board ?


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The last thing you did is where you should start looking.
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power the the processor with 12V DC.
+12 anode of 1N4007 cathode to 7805 regulator input, 7805 regulator output is +5V.
Of course you will power the 7805 with 12V and feed the o/p of the 7805 to the processor VCC(7) and AVcc(20) .
Aref(21) to 100nf to ground.
VCC(7) to 100nF to ground.
AVcc(20) to 100nF to ground.

* 2014-07-09_16-53-35.jpg (7.07 KB, 308x333 - viewed 11 times.)
« Last Edit: July 09, 2014, 05:55:36 pm by LarryD » Logged

The way you have it in your schematic isn't the same as how you have it wired up!

Lacey, Washington, USA
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5V and -only- 5V connects to both Vcc and AVcc. Do NOT connect 12V to those pins. It should go to ground and the input of the 7805, seen here:

That page is flawed - there should be several 0.1uF bypass caps across both power rails, one right at AVcc, and on ARef.

Steve Greenfield AE7HD
CET Consumer Electronics and Computer
Please don't read your attitudes into my messages

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