Hi there,I recently got my DS3231 module labeled ZS-042 off of ebay and it came with a CR2032 3V battery.The module works at 3.3V and also 5V however after some days of usage at 5V I noticed that the battery has become quite "thick". A quick check with the multimeter confirms that the module force-charges the battery with VCC! Not quite nice. Here a pic:So you should at least power this module only at 3.3V, even then, question to the experts: is it save to "charge" a 3V CR2032 at 3.3V continuously without it breaking after some time? 2nd question: is it ok to charge a LIR2032 at 5V?Other than that the module works quite well with the time library Edit: corrected 3202<>2032 messup
HiThought this might help....The use of a LIR2032 could well work fine if you leave the circuit as it is and use a 5V supply.The LIR2032 can have a maximum charge voltage of 4.2V and a maximum charge current of 35mA.Someone is saying in the discussion that they measured 4.2V between the diode and the 200ohm (201) resistor. Assuming that is correct, that takes care of the maximum charge voltage for the LIR2032.The resistor will take care of the max charge current for the LIR2032, because....The current that will pass through the 200 ohm resistor (resistor 201) to the battery is the voltage across the resistor divided by its resistance.So in the worst case the maximum current that can ever pass to the battery is;- Voltage between the diode and resistor = 4.2V Voltage the other side of the resistor (battery completely discharged) = 0V Voltage across resistor is therefore 4.2V - 0V = 4.2V Resistors resistance = 200 ohms The current through the resistor and to the battery = (4.2V - 0V) / 200 = 21mAAs the battery charges and its voltage rises the voltage across the resistor will decrease. As the voltage across the resistor decreases so will the current to the battery. e.g. Assume the battery has charged to 3.0V The current through the resistor and to the battery will be = (4.2V - 3V) / 200 = 6mASo as the battery gets closer to being fully charged the current to it will drop and effectively will provide a trickle charge for the battery.... RegardsGypo
Hey guys,I have a different question to the RTC Module but didn´t want to open a new thread.So I was calling the Module over I2C address 0x68. Since I upgraded my sketch, I now need to use a different address. I always thought I could alter the address shorting the A0, A1 or A2 pins. I shorted the A1 pin. The address should be 0x6A then right?Unfortunately I still get an answere from the RTC via the address 0x68.What am I doing wrong??Thx in advance...heni40
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