Go Down

Topic: Non-Int Storage in EEPROM. (Read 460 times) previous topic - next topic



I am trying to store either a float or a double to the EEPROM.
How would I go about doing this? the library currently only supports integers,
I have read about bitwise operators but I was unable to find anything related to my problem.

Thank you


You can use a union to access each byte of the 4-byte float. A union is similar to a struct, except that it only allocates enough space to contain the largest single type that is defined inside it. Here's an example of how to copy a float byte by byte from the original to another, using C++ on a PC.

Code: [Select]
#include <iostream>
using namespace std;

union bitFloat {
     float float_num;
     char byte[4];

int main()
     bitFloat test;
     test.float_num = 10.5f;
     bitFloat test2;
     test2.byte[0] = test.byte[0];
     test2.byte[1] = test.byte[1];
     test2.byte[2] = test.byte[2];
     test2.byte[3] = test.byte[3];

     cout << test.float_num << endl;
     cout << test2.float_num << endl;

     return 0;

The important thing to realise is that the bitFloat type defined is only 4 bytes, and you have two ways of accessing its data - one through the float type test.float_num or through the byte array, test.byte.
So, the practical upshot of all this is that you can store your floating point numbers in EEPROM, and read them out byte by byte, and use them to build up your whole float variable. (floats and doubles are both 4 bytes on the AVR cores.) The only thing you might have to worry about is endian-ness... which order the bytes need to be stored in. Unfortunately I don't know myself what the AVRs are. ):

Go Up

Please enter a valid email to subscribe

Confirm your email address

We need to confirm your email address.
To complete the subscription, please click the link in the email we just sent you.

Thank you for subscribing!

via Egeo 16
Torino, 10131