Here's how I'd think about it. You have a 0.5F cap charged to 3.5V, right? The capacitor discharge equation says that I=C*dV/dt where I is current (~50mA), C=0.5F, and dV is how much the voltage is going to change. Let's say you're willing to let the voltage discharge to 3.3V, then dV=3.5-3.3=0.2V.From this you can solve for dt:dt = C*dV/I = 0.5*0.2/0.05 = 2So I'm afraid this will only last 2 seconds until it reaches 3.3V --The Aussie Shield: breakout all 28 pins to quick-connect terminals
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