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Topic: VERY basic math resistor question. (Read 2045 times) previous topic - next topic

Jaykey


Well, I am trying to learn some of the real math and what it does etc. for practical use as my Arduino won't be here for a week or two so I figure hey! lets design the worlds simplest circuit.

So I decide to light an LED.

This leads me too the datasheet on an LED.
On the sheet I THINK I understood that their were two requirements.
1. Forward voltage should not exceed 3 Volts.
2. Forward current should be 20mA
3. lets use a 9v power supply.

So my next thought IS that this should be easy. Ohms law.
9v/20mA = 4.5kOhm(I think, my decimals need reviewed) BUT, this doesn't account for voltage. How does the resistor play into the voltage etc.

James C4S

In terms of Voltage, components in series add up.  So if your LED drops 3v, how much of the 9v is left for the resistor to drop?
Capacitor Expert By Day, Enginerd by night.  ||  Personal Blog: www.baldengineer.com  || Electronics Tutorials for Beginners:  www.addohms.com

CrossRoads

Forward voltage is how much the voltage drop is across the diode when it is on.
So if you hooked it up the anode to a 5v power source (such as an arduino output pin) there would be 2V at cathode.
To control the current, that 2V/20mA would need a 100 ohm resistor.
3V sounds kind of high for forward voltage, I would check that.

The other thing listed is the reverse voltage, such as shown here:
http://www.mpja.com/prodinfo.asp?number=11017+OP
If the Max reverse voltage is 5v such as this one, then 9V is too high to drive it with.
Designing & building electrical circuits for over 25 years.  Screw Shield for Mega/Due/Uno,  Bobuino with ATMega1284P, & other '328P & '1284P creations & offerings at  my website.

Jaykey

Okay. Thanks.

The numbers are mostly hypothetical so they may not be realistic.

Okay, my LED drops 3v, and I got a 9v supply. So I need to remove 6 volts with the resistor and provide 30 mA of current...

Soooo

6/.030 = 200 ohm resistor?

And what is this REVERSE voltage? Surely people can hook up leds to 9v with proper resistors etc.? (I have no idea what I'm saying, I want more information though.


CrossRoads

Your math is correct.

Reverse voltage is how much voltage can be held off before the LED may be damaged when it should be off.
A diode conducts current when a forward voltage is applied, but will not conduct if a reverse voltage is applied, up to a point. Reverse voltages in excess of the maximum can cause the diode to fail.
http://led.linear1.org/what-are-the-electrical-characteristics-of-leds/

If the max reverse voltage is 5v and you using a 9V source, pay attention when hooking things up.
Designing & building electrical circuits for over 25 years.  Screw Shield for Mega/Due/Uno,  Bobuino with ATMega1284P, & other '328P & '1284P creations & offerings at  my website.

Jaykey

YAY!!! My math is correct.

In regards to "reverse voltage".

What I am confused with is IF my resistor drops the voltage down to the proper level and bleeds the right current, how could the led get burnt out? When it mentions "reverse voltage" I immediately think of what would happen if I wired it backwards etc. (Thanks again so far.)

CrossRoads

#6
Feb 18, 2011, 08:32 am Last Edit: Feb 18, 2011, 08:36 am by CrossRoads Reason: 1
Well, I had a 12V source with 2 LEDs and a NPN transistor to turn them on/off.
(I also had strings of 5 LEDs from 12V for another indicator, so 12v was conveniently available for these 2.)
What I found was that when off, with the base of the transistor grounded even, the LEDs looked like they were on. If I had 3 LEDs they would turn off okay (but my design called for 2). I ended up using 2 LEDs from a 5v source instead to get them to turn off.
Maybe my transistor had  a lot of leakage.
I don't know if your LED will have a similar issue from 9V.

Here's a picture of them on, with the base (middle pin) connected to the emitter (bottom pin) which was connected to arduino ground.
The wallwart power supply was marked 12v, but when measured was actually more like 14.
Designing & building electrical circuits for over 25 years.  Screw Shield for Mega/Due/Uno,  Bobuino with ATMega1284P, & other '328P & '1284P creations & offerings at  my website.

Jaykey


Sounds like you have had some interesting LED issues. Sounds like a grounding issue and the NPN circuit IMHO...but I have no idea what I am talking about.

As I am a TOTAL noob at this moment I'm more of in the what does these numbers mean...how do I get it to do what it wants phase. Thanks for the guidance so far, I'm sure I will have a BILLION more questions.

Jaykey

One more question.

Trying to apply my new knowledge.

Just supposing, and NO I'm not going to do this, power outlet...

120V to LED(30mA, 3v).
120V-3V = 117V
117V/.030 = 3900Ohm

I was thinking about WHY this might not work and then I asked, How many Watts can the Resistor handle?
Watts = Current x Volts.
.03Amps * 120 = 3.6 Watts.

SOOOO... could I 4 watt 3.9KOhm resistor run this LED from the wall?

CrossRoads

You will have 1 lead of the LED at ground yes? While the other leg swings up & down from -60V to +60V effectively?
What is the max reverse voltage of your LED?
I'm thinking it would go POOF! pretty quick :)
Designing & building electrical circuits for over 25 years.  Screw Shield for Mega/Due/Uno,  Bobuino with ATMega1284P, & other '328P & '1284P creations & offerings at  my website.

CrossRoads

On the LED/transistor issue, I am not quite sure what it was. The LEDs were not on very bright, not as compared to their on state which was blindingly bright (10000mCD white LEDs, hurt the eyes to look at it), but they were clearly not all the way off either. If I had 3-4-5 LEDs in series it was fine. But 1 or 2, and they would be on some.
Designing & building electrical circuits for over 25 years.  Screw Shield for Mega/Due/Uno,  Bobuino with ATMega1284P, & other '328P & '1284P creations & offerings at  my website.

Jaykey

Okay, I think I am figuring out how I am confused, I think.

If I am running DIRECT CURRENT is reverse voltage a factor? Cause with AC it would make sense that the whole circuit would blow up from the alternating, but if I had a mythical 120V DC source, would it work?

I'm still confused as hell about this reverse voltage stuff. Is it AC related as my 9V etc. is all DC...I think.

retrolefty


One more question.

Trying to apply my new knowledge.

Just supposing, and NO I'm not going to do this, power outlet...

120V to LED(30mA, 3v).
120V-3V = 117V
117V/.030 = 3900Ohm

I was thinking about WHY this might not work and then I asked, How many Watts can the Resistor handle?
Watts = Current x Volts.
.03Amps * 120 = 3.6 Watts.

SOOOO... could I 4 watt 3.9KOhm resistor run this LED from the wall?



Not without an addition component. You wall output power is AC, so it offers both positive and negative voltages, swapping back and forth 60 times a second. All is good in your circuit when the AC voltage polarity is such that the led is being forward biased, i.e. cathode terminal negative relative to anode. However when the AC flips polarity the led becomes reversed biased and you run up against the leds maximum reversed bias voltage before breakdown specification. This results in  flames, screaming disaster, magic smoke raising in the air. As no current can flow when reversed biased there is no voltage drop across the series resistor so the led 'feels' the full AC voltage and that is much higher then the led's max reverse voltage rating.

So what additional component will save your day in your circuit? Just wire a series diode that will only allow current to flow in one direction, so the led never 'feels' the high reversed bias voltage. A 1N4004 will work fine. This new diode acts like a switch or check-valve, only allowing forward current to flow.

Make sense?

CrossRoads

So your LED will be turning on/off eventually, yes? What plans do you have for controlling it?
Here are some simple connections you can make that an arduino output pin can control.
Designing & building electrical circuits for over 25 years.  Screw Shield for Mega/Due/Uno,  Bobuino with ATMega1284P, & other '328P & '1284P creations & offerings at  my website.

Jaykey

#14
Feb 18, 2011, 09:22 am Last Edit: Feb 18, 2011, 09:30 am by Jaykey Reason: 1
Thanks for the clarification.

To clarify, I'm looking at a data sheet (hypothetical, not real) on LEDs and am trying to design a most basic circuit.


Am I correct in that REVERSE VOLTAGE errr... is only a concern when working with AC?

It is the post below that confuses me.

I see simple example circuits with LEDs, one resistor, an LED, and a power source. Why do these not have reverse voltage issues? What IS reverse voltage. Does it apply to a DC circuit *note, I have not gotten to AC circuits yet, so I know nothing of them. ARGH!!! *Tears hair out*


Quote

Your math is correct.

Reverse voltage is how much voltage can be held off before the LED may be damaged when it should be off.
A diode conducts current when a forward voltage is applied, but will not conduct if a reverse voltage is applied, up to a point. Reverse voltages in excess of the maximum can cause the diode to fail.
http://led.linear1.org/what-are-the-electrical-characteristics-of-leds/

If the max reverse voltage is 5v and you using a 9V source, pay attention when hooking things up.


Reading a little more.
Was this entire extended discussion due to "don't wire it backwards?"

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