Poll
 2 6 (33.3%) 288 10 (55.6%) Go create something! 2 (11.1%)
Total Voters: 18

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 Author Topic: 48÷2(9+3) = ?  (Read 7243 times) 0 Members and 1 Guest are viewing this topic.
Silly-con Valley, Ca, U.S.
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 « on: April 14, 2011, 11:37:02 am » Bigger Smaller Reset

I've seen this on 2 different forums and it seems about 50/50 that people get it right. And hilariously the people who don't are adamant they are right. Let's see what happens here.

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10 PRINT CHR$(7) 20 GOTO 10 Lancashire, UK Offline Edison Member Karma: 9 Posts: 1991  « Reply #1 on: April 14, 2011, 11:49:34 am » Bigger Smaller Reset 288 or 2 depending on how you look at it. It would need some extra brackets to be unambiguous I think.  Logged The Netherlands Offline Full Member Karma: 2 Posts: 178 Beep!  « Reply #2 on: April 14, 2011, 12:47:24 pm » Bigger Smaller Reset I'm going with 2  Logged Silly-con Valley, Ca, U.S. Offline Sr. Member Karma: 17 Posts: 420 Lernin' to tinker  « Reply #3 on: April 14, 2011, 01:02:18 pm » Bigger Smaller Reset ...depending on how you look at it. It's math. There can only be 1 answer.  Logged 10 PRINT CHR$(7)
20 GOTO 10

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I don't think you connected the grounds, Dave.
 « Reply #4 on: April 14, 2011, 01:06:07 pm » Bigger Smaller Reset

It's an obvious inequality
'?' = 63
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"Pete, it's a fool looks for logic in the chambers of the human heart." Ulysses Everett McGill.
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 « Reply #5 on: April 14, 2011, 01:36:24 pm » Bigger Smaller Reset

288 makes more sense to me. I know why some answers 2 (obviously different order of calculation) but I can't think of a reason for 63. Your turn AWOL.
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20 LEDs are enough
 « Reply #6 on: April 14, 2011, 01:45:37 pm » Bigger Smaller Reset

\begin{smartass}
You might expect 288. However you neither told the base for the number representation, nor the underlying field or ring in which to do the calculation. Assuming decimal representation and computations in Z you get 288. Hexadecimal in Z you get 1B0. Decimal representation computing in GF2 you have a division by 0. So you can get almost anything you want if you tweak the ring and/or the representation accordingly.

And you think 50% of the people get this right? I am impressed
\end{smartass}
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20 LEDs are enough
 « Reply #7 on: April 14, 2011, 01:54:32 pm » Bigger Smaller Reset

@liudr: AWOL assumes ? == '?' because '?' == 63. So what he says is 48÷2(9+3) = ? is wrong and 48÷2(9+3) != ? would be right.
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Central MN, USA
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 « Reply #8 on: April 14, 2011, 01:55:54 pm » Bigger Smaller Reset

I think you're smart. On the other hand, I didn't say my 288 was decimal. I could have different base on each digit, and fractional or irrational base to make 288 equal a lot of things.
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20 LEDs are enough
 « Reply #9 on: April 14, 2011, 01:57:47 pm » Bigger Smaller Reset

Depending on the base and/or ring. That's what I said. But the OP said 50% of the people get this right...
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20 LEDs are enough
 « Reply #10 on: April 14, 2011, 02:01:20 pm » Bigger Smaller Reset

Why not switch to Z/1Z and make your 288 equal to "anything"
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Central MN, USA
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 « Reply #11 on: April 14, 2011, 03:04:43 pm » Bigger Smaller Reset

Yeah! In one of the recent exams I gave, I mentioned one senior professor in my department claims to be 35, base n years old and had my student estimate his base.
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I don't think you connected the grounds, Dave.
 « Reply #12 on: April 14, 2011, 03:08:39 pm » Bigger Smaller Reset

On second thoughts, '?' could also be 111
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Do not send technical questions via personal messaging - they will be ignored.

Silly-con Valley, Ca, U.S.
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 « Reply #13 on: April 14, 2011, 03:43:24 pm » Bigger Smaller Reset

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10 PRINT CHR\$(7)
20 GOTO 10

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 « Reply #14 on: April 14, 2011, 03:57:43 pm » Bigger Smaller Reset