My guess is that you are maxing-out the capacity of the output pins on the board.
reconnecting it with a diode to prevent current flow. Probably there's a good reason to not do that.
Quotereconnecting it with a diode to prevent current flow. Probably there's a good reason to not do that.This is a hairy area. The diode is going to drop 0.7v. So 5v - 0.7v is 4.3v. And I am assuming a nominal 5v.
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