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### Topic: Simple Transistor Question (Read 930 times)previous topic - next topic

#### aKiwi

##### May 28, 2011, 12:39 pm
Hello fellow peeps!

When i use -> digital(pin, HIGH) for the base pin on my little transistor (2N3904) i get everything working.
But if i use the 5v pin from Ardunio it doesn't..

What basic principle am i missing here?

/slightly confused

#### jackrae

#1
##### May 28, 2011, 01:03 pm
Do you have a base current limiting resistor (say 4k7) in the transistor base connection.  If not then the base junction is causing a (almost) dead short across the supply line.  Why would you want to connect the base to the 5volt line ?

#### markbee

#2
##### May 28, 2011, 02:41 pm
in fact you almost always need a base resistor. for the common npn-transistors like 2n3904 or bc547 etc. it's quite easy to calculate if you want to use the transistor as a switch:

Rbase = Uvcc-Ube/ Ibase => Rbase = (5 volt-0,7volt)/0,002A = 2150 ohms.

So if you want to drive the transistors base with 2 mA you need a resistor to the base of about 2k2 ohms.

markbee
XBee blog: http://lookmanowire.blogspot.com/

#### aKiwi

#3
##### May 29, 2011, 02:31 am
Thanks for the replies.

My basic newb thinking was that iirc, digitalwrite at high was = to 5v, so with some quick proof of concept testing i thought it should do the same thing.

Clearly i have much to learn.

Thanks.

#### James C4S

#4
##### May 29, 2011, 02:49 am
Quote
My basic newb thinking was that iirc, digitalwrite at high was = to 5v, so with some quick proof of concept testing i thought it should do the same thing.

The difference wasn't explicitly stated:  the I/O pin limited the current to the transistor, the 5V supply did not.  Neither is a good thing, because the I/O pins are not designed to be current limiters.  As already stated, you should always have a current limiting resistor connected to the base of the transistor (in cases where you are using it as a switch.)

With a current limiting resistor in series with the base, the I/O pin and 5V supply will work the same for turning on the transistor.
Capacitor Expert By Day, Enginerd by night.  ||  Personal Blog: www.baldengineer.com  || Electronics Tutorials for Beginners:  www.addohms.com

#### aKiwi

#5
##### May 29, 2011, 04:58 am
Thanks for that James.

Have used this transistor with another 9v circuit, running pwm with no resistor.

Duly noted, if using as a switch - need resistor. (With calc used above)

Used a 1R2 (instead of 2150 ohms) resistor for a test and it held it open and then faded out. So i think i need to do some googling to further my knowledge.

Thanks for the help.

#### Grumpy_Mike

#6
##### May 29, 2011, 05:41 am
Quote
Used a 1R2 (instead of 2150 ohms)

In this context a 1R2 resistor is just like no resistor at all. Unless you mean a 1K2.

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