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Topic: WS2803 versus WS2801 (Read 17 times) previous topic - next topic

KirAsh4

#35
Oct 25, 2012, 09:55 pm Last Edit: Oct 25, 2012, 09:58 pm by KirAsh4 Reason: 1

I refer to color, color palette, which can generate these libraries.
the library WS2801 says 24bit full color "speed PWM drivers for 24 bit color per pixe". but the WS2803?


Read the datasheet.  Do your own calculations like I did above.  They both provide 24 bits per pixel.  2801 only drives one RGB pixel (or group.)  2803 drives 6 RGB pixels (or groups): 6 x 24 = 144 bits, which is what the 2803 needs.


another question, I have connected to chit WS2803 with 3.3 volts. rgb led smd and 5050, without resistance, lights and all, but when I try main SW RGB LEDs blink while this is not a constant light.
I think that no resistance, that resistance should agregarles?


Again, read the datasheet.  A resistor is required to set the proper current.  You can't expect it to work properly if you don't follow the datasheet's instructions.  If you want to go at it in your own way, that's great.  It makes for fun experimenting.  However, you have to expect things to behave very different than what's expected from them.


Here the datashiit of LEDs

http://www.ebay.com/itm/100-pcs-New-RGB-PLCC-6-5050-3-CHIPS-SMT-SMD-LED-Light-/170786097936?pt=LH_DefaultDomain_0&hash=item27c3a50b10


Those are the same ones I use and they work great, both with the 2801 as well as the 2803.  The difference is, the 2803 requires 144 bits of data (8 bit per channel), whereas the 2801 only needs 24 (again, 8 bits per channel.)

Omnimusha

#36
Nov 06, 2012, 02:12 am Last Edit: Nov 06, 2012, 02:18 am by Omnimusha Reason: 1
ok, then.......





http://subefotos.com/ver/?a36a2513e7065f040792f69824e66389o.png


okay my calculations?

regards!!

KirAsh4

Calculations for what exactly?


KirAsh4

Still, I have no idea what he's calculating.  That figure has to do with the supply to the IC, not what the LEDs need for current.  The datasheet also specifically states what size resistor is needed for a 20mA current output.  So I have no idea what he's trying to calculate here.  But then, this is what happens when people don't bother to actually *read* the datasheet.

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