next topic »

[on:]

i'm try to make a quiz for my project however im encountering a problem when the user have to chose the answer as the previous output is being outputted. the above is my code


void loop() {
  // set the cursor to column 0, line 1
  // (note: line 1 is the second row, since counting begins with 0):

  // print the number of seconds since reset:
    buttonState = digitalRead(buttonPin);
    lcd.setCursor(1, 7);
  for(i=0;i<1;i++){
  if (buttonState == HIGH) {     
    // turn LED on:
   
    lcd.print("SPORTS WAS CHOSEN");
    delay(1000);
    lcd.clear();
    lcd.setCursor(0, 0);
    buttonState == LOW;
  }
  } 
    lcd.print("Which team won ");
    lcd.setCursor(0, 1);
    lcd.print("the World cup?");
    lcd.setCursor(0, 2);
    lcd.print(" a. A");
    lcd.setCursor(0, 3);
    lcd.print(" B. B");
    buttonState = digitalRead(buttonPin);
    if(buttonState == HIGH){
     
         lcd.print(" Wrong answer ");
         digitalWrite(led, HIGH);
         delay(1000);
    }
  }

[Reply #1 on:]

Try a single = here:

    lcd.print("SPORTS WAS CHOSEN");
    delay(1000);
    lcd.clear();
    lcd.setCursor(0, 0);
    buttonState == LOW;   <<<
  }

[Reply #2 on:]

first of all thanks for your help

i try that but the problem is that when i'm pushing the swicth again the bulb is going on and also the text "sport was chosen"

[Reply #3 on:]

okay, you are probably seeing "button bounce"

Go check the Learning section for "debounce" so the button is only read once when pressed.

[Reply #4 on:]

Code:

  for(i=0;i<1;i++){

Please explain that.

[Reply #5 on:]

it basically  loops for 1 time i did to experiment.  however it does noting