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« Reply #30 on: March 25, 2012, 11:46:01 pm » |
Thanks guys. GoForSmoke you are correct and thanks for the remark.
Tom, actually I haven't paid attention to that part (...) and IDLE is indeed no longer needed.
Is there a way for me to now take the array and smooth its curve of values so as to get rid of small jitters? Do you believe a stepper motor could do a better job of moving smoothly? The servo moves a focus ring on a lens. Do you think an optical encoder w/high resolution will help that (or maybe the 180 degree resolution of the servo limits me?
Thank you
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« Reply #31 on: March 27, 2012, 02:50:14 pm » |
I'm looking all over the place, and I guess it's just my lack of understanding  , but I can't find a decent example of a continuous array being smoothed - not just averaged. What I mean is that if in the course of 300 values from 0 to 299 I have parts like: 234, 235, 238, 236, 239, 240, 241 I can smooth the curve to 234, 235, 236, 237, 238, 239, 240 Any pointer? Thanks
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« Reply #32 on: March 27, 2012, 03:21:56 pm » |
Just sort it?
Look up: qsort
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« Reply #33 on: March 27, 2012, 03:24:27 pm » |
No Nick - I mean smoothing the curve between the values so as to get rid of unwanted jitter
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In theory there is no difference between theory and practice, however in practice there are many...
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« Reply #34 on: March 27, 2012, 03:29:46 pm » |
234, 235, 238, 236, 239, 240, 241
I can smooth the curve to
234, 235, 236, 237, 238, 239, 240
should be smoothed to: 234, 235, 236, 238, 239, 240, 241 Nick was in the right direction, with sorting, but instead of sorting the whole array you must sort a small window. you can use a single pass of bubble sort to remove jitter with a window size of 2 values. You can create algorithms that do smoothing upon 2,3,4,..100 values that are basicly al the same. get the idea?
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« Reply #35 on: March 27, 2012, 03:35:10 pm » |
Unfortunately... far from it  I mean, I understand the idea but not how to take my arrays and do this. I hate to admit it but the whole "create algorithms" stuff is for me like "write a poem in Chinese"...
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« Reply #36 on: March 27, 2012, 04:08:03 pm » |
Well, do a single pass through the array. If two values are in the wrong order, swap them.
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« Reply #37 on: March 27, 2012, 05:34:51 pm » |
I don't think sorting is the right option. How would it handle decrements? Sounds like what he's looking for is more of a lowpass filter algorithm. Maybe a good place to start would be to average three values at a time, and set the middle to the average. Consider this sequence: 200 205 210 220 212 214 212 209 199 209 200 There are spikes up at 220 and down at 199. If you wrote a procedure to take (index) and (index + 2) and average them, then write that to (index + 1), you end up with: 200 205 212 212 213 212 210 205 207 203 200 You end up distorting the actual values, but smooth the response considerably. Maybe it's a good trade, maybe it isn't, but it's an easy loop to code: // Loop from first entry to two-from-last entry // (Can't use next-to-last or last indexes because i+2 is out of bounds) for (int i = 0; i < max - 2; i++) { array[i + 1] = (array[i] + array[i + 2]) / 2; } edit: Ugh, I swear.. I need to learn to proof-read. I've edited this like four times to fix things.
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« Last Edit: March 27, 2012, 05:38:04 pm by SirNickity »
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« Reply #38 on: March 27, 2012, 11:42:44 pm » |
I'm looking all over the place, and I guess it's just my lack of understanding  , but I can't find a decent example of a continuous array being smoothed - not just averaged. What I mean is that if in the course of 300 values from 0 to 299 I have parts like: 234, 235, 238, 236, 239, 240, 241 I can smooth the curve to 234, 235, 236, 237, 238, 239, 240 Any pointer? Thanks You want curve fitting or can you live with a linear fit? That's possibly a major scope in itself. The quick and easy for curve fitting would be to transfer the data to your PC and use an application there. Perhaps a spreadsheet or matlab?
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Examples can be found at Learning in the Main Site and at the Playground
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« Reply #39 on: March 28, 2012, 12:02:29 am » |
oohh, seems like I'm stepping into deep water here - for me at least... Thank you all for replying  Nick - how do I do what you suggest? I'd be happy to try and see if it works. SirNickity - I'm going to try and use your suggestion and see what comes at the other side. Thanks. GoForSmoke - I think linear would suit me fine (and I don't want to use a pc). Does that mean using SirNickity's technique? Or are you talking about some other way of doing this?
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« Reply #40 on: March 28, 2012, 12:52:53 am » |
Nick - how do I do what you suggest? I'd be happy to try and see if it works.
Something like this does some local smoothing: int test [] = { 1, 2, 3, 5, 4, 6, 7, 234, 235, 238, 236, 239, 240, 241, 40, 41, 44, 43, 42, 45, 46, 47 }; // number of items in an array #define NUMITEMS(arg) ((unsigned int) (sizeof (arg) / sizeof (arg [0]))) void setup () { Serial.begin (115200); Serial.println (); for (int i = 0; i < NUMITEMS (test) - 2; i++) { if (test [i + 1] > test [i + 2] && test [i] < test [i + 2]) { // swap this and next int temp = test [i + 1]; test [i + 1] = test [i + 2]; test [i + 2] = temp; } // end of if } // end of for for (int i = 0; i < NUMITEMS (test); i++) Serial.println (test [i]); } // end of setup void loop () {} Output: 1 2 3 4 5 6 7 234 235 236 238 239 240 241 40 41 43 44 42 45 46 47
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« Reply #41 on: March 28, 2012, 01:43:45 am » |
Thanks Nick, I think I understand, only it seems quite a problem to do this for an array containing 500 values... I'll also check qsort as you recommended.
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« Reply #42 on: March 28, 2012, 02:14:13 am » |
Thanks Nick, I think I understand, only it seems quite a problem to do this for an array containing 500 values...
Why? I'll also check qsort as you recommended. qsort will only sort the whole thing into sequence. That may or may not be what you want.
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« Reply #43 on: March 28, 2012, 07:32:18 am » |
Hey SirNickity - I'm using your idea and something weird is happening... It does indeed smooth the values, but on "playback mode" I get weird values at the start... I'm attaching the code and would appreciate your observance... // // FILE: servoRecorder.pde // AUTHOR: Adi Soffer // DATE: 28-3-2012 // // PUPROSE: servo recorder //
#define IDLE 0 #define FREE 1 #define RECORD 2 #define PLAYBACK 3 #define STOP 4 #define REWIND 5 #define RECORDCONT 6
int mode; int idx, lastidx, firstidx, newidx; int maxidx = 800;
#include <Servo.h>
Servo myservo; // create servo object to control a servo char buffer [2]; //variable to hold keystrokes int potpin = 0; // analog pin used to connect the potentiometer unsigned int val; // variable to read the value from the analog pin const unsigned int valNumber = 800; //variable to contain number of array members int incomingByte; //declare variable to hold incoming letter unsigned int servoPos[valNumber]; //create array of values for servo position const int waitForServo = 15; //delay time to let servo get to position
const byte recordModeLed = 3; // defining pins for ui leds const byte homeModeLed = 4; const byte playModeLed = 5; const byte freeModeLed = 6; const byte freeSwitch = 7; //defining pins for switches const byte recSwitch = 8; const byte homeSwitch = 9; const byte playSwitch = 10;
void setup() { Serial.begin(9600); Serial.flush(); myservo.attach(2); // attaches the servo on pin 2 to the servo object pinMode (freeModeLed, OUTPUT); //defining LED pins as output pinMode (recordModeLed, OUTPUT); pinMode (homeModeLed, OUTPUT); pinMode (playModeLed, OUTPUT); pinMode (freeSwitch, INPUT); //defining switch pins as input pinMode (recSwitch, INPUT); pinMode (homeSwitch, INPUT); pinMode (playSwitch, INPUT); }
void loop () { digitalWrite (freeModeLed, LOW); digitalWrite (recordModeLed, LOW); digitalWrite (homeModeLed, LOW); digitalWrite (playModeLed, LOW);
// HANDLE IO
if (Serial.available( ) > 0) { incomingByte = Serial.read ( );
switch(incomingByte) { case 'f': mode = FREE; Serial.println ("Free mode"); break; case 'r': mode = RECORD; for (int c=6;c>3;c --) // three sec LED countdown to recording { digitalWrite (recordModeLed, HIGH); digitalWrite (c, HIGH); delay (700); digitalWrite (recordModeLed, LOW); digitalWrite (c, LOW); delay(300); } Serial.println ("Record"); break; case 's' : mode = STOP; Serial.println ("STOP"); break; case 'w' : mode = REWIND; digitalWrite (homeModeLed, HIGH); //turn on rewind LED Serial.println ("Rewind"); break; case 'p': mode = PLAYBACK; digitalWrite (playModeLed, HIGH); //turn on playback LED Serial.println ("Playback"); break;
} }
switch(mode) {
case STOP: for (int x=3;x>6;x++) { digitalWrite (x, LOW); //turn off all LEDs } break;
case FREE: digitalWrite (freeModeLed, HIGH); val = analogRead (potpin); val = map(val, 0, 1023, 0, 179); // val = val * 45/256; // <==> val * 180/1024 myservo.write (val); Serial.println (val); //print val for checking newidx == val; delay (waitForServo); // should be refactored away -> like blink without delay break;
case RECORD:
digitalWrite (recordModeLed, HIGH); //keeps LED on Serial.println ("Record function"); // if so - prints record val = analogRead(potpin); // reads the value of the potentiometer (value between 0 and 1023) val = map(val, 0, 1023, 0, 179); // scale it to use it with the servo (value between 0 and 180) myservo.write(val); // sets the servo position according to the scaled value Serial.println (val); // print values for checking servoPos [idx]=val; // stores val in array "servoPos" firstidx = idx; mode = RECORDCONT;
break;
case RECORDCONT: digitalWrite (recordModeLed, HIGH); //keeps LED on val = analogRead(potpin); // reads the value of the potentiometer (value between 0 and 1023) val = map(val, 0, 1023, 0, 179); // scale it to use it with the servo (value between 0 and 180) myservo.write(val); // sets the servo position according to the scaled value servoPos [idx]=val; // stores val in array "servoPos idx ++ ; lastidx = idx; if (idx == maxidx) mode = STOP; delay(waitForServo); // waits for the servo to get there Serial.println(val); // print values for checking
break;
case REWIND: //need to build rewind from new point in free mode
newidx = analogRead (potpin); if (newidx = lastidx) { for (int i=lastidx;i>firstidx;i--) { myservo.write (servoPos [i]); val = servoPos [i]; delay (waitForServo); Serial.println (val); // print values for checking } } else //need to build rewind from new point in free mode { } mode = STOP; for (int x=3;x>6;x++) { digitalWrite (x, LOW); //turn off all LEDs } break;
case PLAYBACK: for (int x = 0;x<lastidx - 2; x++) // smoothing values { servoPos [x+1] = (servoPos [x] + servoPos [x+2] ) /2; } for (int i=firstidx; i< lastidx; i++) { myservo.write (servoPos[i]); val = servoPos [i]; delay (waitForServo); Serial.println (val); //print val for checking } mode = STOP; for (int x=3;x>6;x++) //turn off all LEDs { digitalWrite (x, LOW); } break;
} }
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« Last Edit: March 28, 2012, 07:39:42 am by Soffer »
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« Reply #44 on: March 28, 2012, 07:47:01 am » |
I'm not sure but I think my code doesn't take care of erasing the values in array in every new recording. Is there a way to do that?
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